Mr. Armstrong Please create a C-programming code to check whether a number is an Armstrong number or not. An Armstrong number is a number which is equal to the sum of digits raise to the power of the total number of digits in the number. Some Armstrong numbers are: 0, 1, 2, 3, 153, 370, 407, 1634, 8208, etc. The algorithm to do this is: First we calculate the number of digits in our program and then compute the sum of individual digits raise to the power number of digits. If this sum equals the input number, then the number is an Armstrong number otherwise not. Examples: 7 = 7^1 371 = 3^3 + 7^3 + 1^3 (27 + 343 +1) 8208 = 8^4 + 2^4 +0^4 + 8^4 (4096 + 16 + 0 + 4096). Sample Input: 371 Sample Output: Total number of digits= 3 3^3= 27 7^3= 343 1^3= 1 Sum= 371 Thank you!
Mr. Armstrong Please create a C-programming code to check whether a number is an Armstrong number or not. An Armstrong number is a number which is equal to the sum of digits raise to the power of the total number of digits in the number. Some Armstrong numbers are: 0, 1, 2, 3, 153, 370, 407, 1634, 8208, etc. The algorithm to do this is: First we calculate the number of digits in our program and then compute the sum of individual digits raise to the power number of digits. If this sum equals the input number, then the number is an Armstrong number otherwise not. Examples: 7 = 7^1 371 = 3^3 + 7^3 + 1^3 (27 + 343 +1) 8208 = 8^4 + 2^4 +0^4 + 8^4 (4096 + 16 + 0 + 4096). Sample Input: 371 Sample Output: Total number of digits= 3 3^3= 27 7^3= 343 1^3= 1 Sum= 371 Thank you!
C++ for Engineers and Scientists
4th Edition
ISBN:9781133187844
Author:Bronson, Gary J.
Publisher:Bronson, Gary J.
Chapter5: Repetition Statements
Section: Chapter Questions
Problem 7PP
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Mr. Armstrong
Please create a C-programming code to check whether a number is an Armstrong number or not. An Armstrong number is a number which is equal to the sum of digits raise to the power of the total number of digits in the number. Some Armstrong numbers are: 0, 1, 2, 3, 153, 370, 407, 1634, 8208, etc.
The algorithm to do this is: First we calculate the number of digits in our program and then compute the sum of individual digits raise to the power number of digits. If this sum equals the input number, then the number is an Armstrong number otherwise not.
Examples:
7 = 7^1
371 = 3^3 + 7^3 + 1^3 (27 + 343 +1)
8208 = 8^4 + 2^4 +0^4 + 8^4 (4096 + 16 + 0 + 4096).
Sample Input:
371
Sample Output:
Total number of digits= 3
3^3= 27
7^3= 343
1^3= 1
Sum= 371
Thank you!
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