1.) Mr. Aguban is checking the difference in energy between a car battery and a motorcycle battery in moving a certain amount of charge. A 12 V motorcycle battery can move 6,000 C of charge, and a 12 V car battery can move 80,000 C of charge. How much energy does each deliver? Directions: Answer the following set of problem. The scoring is being provided for youbefore the questions.GivenSolutionFinal Answer2 pts5 pts3 ptsSample Problem: An electron is accelerated from rest through a potentialdifference 24 V. What is the change in electric potential energy of the electron?Known :The charge on an electron (e) = -1.60 x 10-19 CoulombElectric potential = voltage (V) = 12 VoltWanted: The change in electric potential energy of the electron (APE)Solution :APE = q V= (-1.60 x 10-19 C)(12 V)= -19.2 x 10-19 JouleThe minus sign indicates that the potential energy decreases.

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Answered: Mr. Aguban is checking the difference…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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1.) Mr. Aguban is checking the difference in energy between a car battery and a motorcycle battery in moving a certain amount of charge. A 12 V motorcycle battery can move 6,000 C of charge, and a 12 V car battery can move 80,000 C of charge. How much energy does each deliver?

Directions: Answer the following set of problem. The scoring is being provided for you
before the questions.
Given
Solution
Final Answer
2 pts
5 pts
3 pts
Sample Problem: An electron is accelerated from rest through a potential
difference 24 V. What is the change in electric potential energy of the electron?
Known :
The charge on an electron (e) = -1.60 x 10-19 Coulomb
Electric potential = voltage (V) = 12 Volt
Wanted: The change in electric potential energy of the electron (APE)
Solution :
APE = q V
= (-1.60 x 10-19 C)(12 V)
= -19.2 x 10-19 Joule
The minus sign indicates that the potential energy decreases.

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