Mr Stat makes a claim the mean age of all his students is 28. His doubting colleagues suspect this average may be too high so they select a sample of 81 students. They find the mean age of the sample is 25.58 with a standard deviation of 7.84. Test the claim at the 0.05 significance level. Part A- Ho: H = Part B - Ha: H Part C-State alpha
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- You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 45 night students, and the sample mean GPA is 2.63 with a standard deviation of 0.81. You sample 40 day students, and the sample mean GPA is 3.02 with a standard deviation of 0.59. Test the claim using a 5% level of significance. Assume the population standard deviations are unequal and that GPAS are normally distributed. Give answer to at least 4 decimal places. What are the correct hypotheses? Ho: M₁ = μ₂ H₁: M₁ Based on the hypotheses, find the following: Test Statistic = -0.7918 X O μ₂ Critical Values=2.0154 x (Just enter the positive CV.) The correct decision is to Reject the null hypothesis The correct summary would be: There is enough evidence to support the claim of night students is different from the mean GPA of day students. o that the mean GPAIt is commonly believed that the mean body temperature of a healthy adult is 98.6° F. You are not entirely convinced. You believe that it is not 98.6° F. You collected data using 53 healthy people and found that they had a mean body temperature of 98.33° F with a standard deviation of 0.93 ° F. Use a 0.05 significance level to test the claim that the mean body temperature of a healthy adult is not 98.6° F. a) Identify the null and alternative hypotheses? Họ: ? H1: ? b) What type of hypothesis test should you conduct (left-, right-, or two-tailed)? left-tailed right-tailed two-tailed c) Identify the appropriate significance level. d) Calculate your test statistic. Write the result below, and be sure to round your final answer to two decimal places. e) Calculate your p-value. Write the result below, and be sure to round your final answer to four decimal places.Suppose that El Camino is studying the average number of hours students study for classes per week. According to research from 2010 El Camino students spent an average of 21 hours a week studying for classes. El Camino wants to study if this average has changed. To do this they take a random sample of 81 current students and find that the average student spent 19.3 hours studying with a standard deviation of 6.4 hours. (Note: You may assume there are approximately 20,000 El Camino students). (a) Carry out a hypothesis test at α = .05 to test the claim that the average number of hours per week that El Camino students study has changed since 2010. (b) Describe what it would mean in this situation to make a Type I error (c) Describe what it would mean in this situation to make a Type II error (d) Construct a 95% confidence interval for the average number of hours studied by El Camino students per week. Make sure to interpret your interval.
- You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 20 night students, and the sample mean GPA is 2.85 with a standard deviation of 0.86. You sample 30 day students, and the sample mean GPA is 3.02 with a standard deviation of 0.4. Test the claim using a 5% level of significance. Assume the population standard deviations are unequal and that GPAs are normally distributed. Give answer to at least 4 decimal places. What are the correct hypotheses?H0: = H1: Based on the hypotheses, find the following:Test Statistic = p− value = The correct decision is to The correct summary would be: that the mean GPA of night students is different from the mean GPA of day students.Fran is training for her first marathon, and she wants to know if there is a significant difference between the mean number of miles run each week by group runners and individual runners who are training for marathons. She interviews 42 randomly selected people who train in groups and finds that they run a mean of 47.1 miles per week. Assume that the population standard deviation for group runners is known to be 4.4 miles per week. She also interviews a random sample of 47 people who train on their own and finds that they run a mean of 48.5 miles per week. Assume that the population standard deviation for people who run by themselves is 1.8 miles per week. Test the claim at the 0.01 level of significance. Let group runners training for marathons be Population 1 and let individual runners training for marathons be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.The mean number of eggs per person eaten in the United States is 223. Do college students eat a different number of eggs than the average American? The 51 college students surveyed averaged 237 eggs per person and their standard deviation was 39.3. What can be concluded at the a = 0.01 level of significance? %3D a. For this study, we should use Select an answer b. The null and altemative hypotheses would be: H 2 Select an answer v H 2vSelect an answer v c. The test statistic ? (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is | ? v a f. Based on this, we should Select an answer V the null hypothesis. g. Thus, the final conclusion is that... O The data suggest that the populaton mean is significantly different from 223 at a = 0.01, so there is statistically significant evidence to conclude that the population mean number of eggs consumed by college students per year is different from 223. Toctor O The data…
- I only need B and CYou are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 20 night students, and the sample mean GPA is 2.94 with a standard deviation of 0.8. You sample 55 day students, and the sample mean GPA is 2.56 with a standard deviation of 0.44. Test the claim using a 1% level of significance. Assume the population standard deviations are unequal and that GPAs are normally distributed. What are the correct hypotheses? Based on the hypotheses, find the following:Test Statistic = Critical Values = ±You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 35 night students, and the sample mean GPA is 2.91 with a standard deviation of 0.97. You sample 20 day students, and the sample mean GPA is 2.99 with a standard deviation of 0.82. Test the claim using a 1% level of significance. Assume the population standard deviations are unequal and that GPAS are normally distributed. Give answer to at least 4 decimal places. What are the correct hypotheses? Ho: M₁ H₁: M₁ Test Statistic = Critical Values = = ± H₁₂ Based on the hypotheses, find the following: ≠v H₂ OF (Just enter the positive CV.) The correct decision is to Fail to reject the null hypothesis The correct summary would be: There is not enough evidence to support the claim ✓ of night students is different from the mean GPA of day students. o that the mean GPA
- You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 30 night students, and the sample mean GPA is 2.83 with a standard deviation of 0.94. You sample 55 day students, and the sample mean GPA is 2.97 with a standard deviation of 0.92. Test the claim using a 1% level of significance. Assume the population standard deviations are unequal and that GPAs are normally distributed. Give answer to at least 4 decimal places. What are the correct hypotheses?H0: Select an answer μ σ² μ₂ p μ₁ x̄₂ s² x̄₁ = Select an answer μ x̄₂ σ² μ₂ x̄₁ μ₁ s² p H1: Select an answer σ² μ x̄₁ s² p x̄₂ μ₁ μ₂ ? = < > ≤ ≠ ≥ Select an answer μ x̄₂ x̄₁ μ₂ σ² s² μ₁ p Based on the hypotheses, find the following:Test Statistic = Critical Values = ±± (Just enter the positive CV.)The correct decision is to Select an answer Reject the null hypothesis Fail to reject the null hypothesis The correct summary would be: Select an answer There is not enough…The mean ACT score for 43 male high school students is 21.1 and the standard deviation is 5.0. The mean ACT score for 56 female high school students is 20.9 and the standard deviation is 4.7. At the 1% significance level, can you reject the claim that male and female high school students have equal ACT score averages? Be sure to use the p-value to make your conclusion.Do shoppers at the mall spend more money on average the day after Thanksgiving compared to the day after Christmas? The 52 randomly surveyed shoppers on the day after Thanksgiving spent an average of $122. Their standard deviation was $29. The 59 randomly surveyed shoppers on the day after Christmas spent an average of $117. Their standard deviation was $35. What can be concluded at the αα = 0.05 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis.