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Một chuyển động có phương trình: R(t) = (cos(4t))i + (sin(4t))j + 4tk. Tìm vector tiếp tuyến đơn vị tại t = 3. O a. T(t)=1/1,414( sin(12,000); cos(12,000); 1) O b. T(t)=1/1,414( sin(12,000); -cos(12,000); 1) -cos(12,000); 1) O c. T(t)=1/1,414(-sin(12,000); O d. T(t)=1/1,414(-sin(12,000); cos(12,000); 1)

Một chuyển động có phương trình: R(t) = (cos(4t))i + (sin(4t))j + 4tk. Tìm vector tiếp tuyến đơn vị tại t = 3. O a. T(t)=1/1,414( sin(12,000); cos(12,000); 1) O b. T(t)=1/1,414( sin(12,000); -cos(12,000); 1) -cos(12,000); 1) O c. T(t)=1/1,414(-sin(12,000); O d. T(t)=1/1,414(-sin(12,000); cos(12,000); 1)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Một chuyển động có phương trình: R(t) = (cos(4t))i + (sin(4t))j + 4tk. Tìm vector tiếp tuyến đơn vị tại t = 3. O a. T(t)=1/1,414( sin(12,000); cos(12,000); 1) O b. T(t)=1/1,414( sin(12,000); -cos(12,000); 1) -cos(12,000); 1) O c. T(t)=1/1,414(-sin(12,000); O d. T(t)=1/1,414(-sin(12,000); cos(12,000); 1)
Transcribed Image Text:Một chuyển động có phương trình: R(t) = (cos(4t))i + (sin(4t))j + 4tk. Tìm vector tiếp tuyến đơn vị tại t = 3. O a. T(t)=1/1,414( sin(12,000); cos(12,000); 1) O b. T(t)=1/1,414( sin(12,000); -cos(12,000); 1) -cos(12,000); 1) O c. T(t)=1/1,414(-sin(12,000); O d. T(t)=1/1,414(-sin(12,000); cos(12,000); 1)
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