Most of the exercises are to provide proofs and illustrations in Euclidean Geometry. Most of these proofs make use of the AA Triangle Similarity Theorem. They may also use the SAS Postulate and/or the ASA, AAS, or SSS Triangle Congruence Theorems or they use the Transversals to Parallel Lines Theorem. You may use paragraph style proofs for the proofs in this homework set. However, you should still be sure to completely justify each step of your proofs. Prove the following proposition. This precedes the AA Triangle Similarity Theorem, so you cannot use it as a reason. Proposition 95. AA Lemma 1 Given AABC with D the midpoint of AB, A-E-C and DE || BC , then 2(DE) ΔAD ~ Δ ΑBC . — ВС, АЕ — ЕC, and

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Geometry 

Most of the exercises are to provide proofs and illustrations in Euclidean Geometry. Most of
these proofs make use of the AA Triangle Similarity Theorem. They may also use the SAS
Postulate and/or the ASA, AAS, or SSS Triangle Congruence Theorems or they use the
Transversals to Parallel Lines Theorem. You may use paragraph style proofs for the proofs in
this homework set. However, you should still be sure to completely justify each step of your
proofs.
Prove the following proposition. This precedes the AA Triangle Similarity Theorem, so you cannot
use it as a reason.
Proposition 95. AA Lemma 1
Given AABC with D the midpoint of AB, A-E-C and DE || BC , then 2(DE)
ΔADE ~ ΔΑBC.
%3D ВС, АЕ — ЕС, and
Transcribed Image Text:Most of the exercises are to provide proofs and illustrations in Euclidean Geometry. Most of these proofs make use of the AA Triangle Similarity Theorem. They may also use the SAS Postulate and/or the ASA, AAS, or SSS Triangle Congruence Theorems or they use the Transversals to Parallel Lines Theorem. You may use paragraph style proofs for the proofs in this homework set. However, you should still be sure to completely justify each step of your proofs. Prove the following proposition. This precedes the AA Triangle Similarity Theorem, so you cannot use it as a reason. Proposition 95. AA Lemma 1 Given AABC with D the midpoint of AB, A-E-C and DE || BC , then 2(DE) ΔADE ~ ΔΑBC. %3D ВС, АЕ — ЕС, and
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