MOMENT OF INERTIA (rotated about the diameter) Mass of Disk, MpisK = 1414.1 g Radius of Disk, RpSK = 11.3 cm Actual value of moment of inertia of disk: |IDISK = (13) Friction Mass = 15 g Radius, r= 1.245 cm (mass of pan + mass added), m Experimental value of moment of inertia, m(g – a)r² Trial Acceleration, a 25 g 0.9 cm/2 1.5 cm/,2 ст (14) 45 g ст (15)
MOMENT OF INERTIA (rotated about the diameter) Mass of Disk, MpisK = 1414.1 g Radius of Disk, RpSK = 11.3 cm Actual value of moment of inertia of disk: |IDISK = (13) Friction Mass = 15 g Radius, r= 1.245 cm (mass of pan + mass added), m Experimental value of moment of inertia, m(g – a)r² Trial Acceleration, a 25 g 0.9 cm/2 1.5 cm/,2 ст (14) 45 g ст (15)
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pls answer with correcct unit and round off into 2 decimals only
Transcribed Image Text:MOMENT OF INERTIA (rotated about the diameter)
Mass of Disk, MpiSK = 1414.1 g
Radius of Disk, RDISK = 11.3 cm
Actual value of moment of inertia of disk:
IDISK =
(13)
Friction Mass = 15 g
Radius, r= 1.245 cm
(mass of pan + mass
added), m
Experimental value of
moment of inertia,
m(g – a)r2
Trial
Acceleration, a
I =
25 g
0.9 cm/2
1.5 cm/2
1
(14)
2
45 g
ст
(15)
TORQUE: SECOND CONDITION OF EQUILIBRIUM
Distance of Object A from
Object A
Torque due to Object A, N-m
center, m
10 kg bricks
80 kg man
3
(16)
(17)
0.80
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