**Moment Diagrams in Frames****Task**: Draw moment diagrams for the frame shown (these will not be turned in). Enter the moment values at the member ends according to the positive sign convention. The frame height is 10 ft and the width is 20 ft.**Diagram Description**:- The diagram is a rectangular frame with points labeled A, B, C, and D.- There is a horizontal member AB on the top left, horizontal member BC on the top right, and vertical members AD and CD.- A moment of 10 kip-ft is applied counterclockwise at the top left corner of the frame at joint B.- Black triangles and circles at joints indicate supports and connections.**Positive Sign Convention**:- Indicated with red arrows showing counterclockwise moments as positive around each joint.**Questions**:1. What is the moment (kip-ft) in member 1 at joint A?2. What is the moment (kip-ft) in member 1 at joint B?3. What is the moment (kip-ft) in member 2 at joint B?4. What is the moment (kip-ft) in member 2 at joint C?5. What is the moment (kip-ft) in member 3 at joint C?6. What is the moment (kip-ft) in member 3 at joint D?

Data given: Asked: Moment in member 1 at joint A Moment in member 1 at joint B Moment in member 2 at joint B Moment in member 2 at joint C Moment in member 3 at joint C Moment in member 3 at joint DConsider ∑V = 0 ∴ VA + VD = 0 Now consider ∑ H = 0 ∴ HA = 0 Finally, consider ∑MA = 0 ∴ VD × 20 + 10 = 0∴ VD = - 1020∴ VD = - 0.5 kip From, VA + VD = 0 VA = 0.5 kip As joint A is hinged support, the value of moment at point A = 0 kip-ftAs there is no horizontal reaction at A, the value of moment in member 1 at joint B = 0The value of moment at joint B = - 10 kip-ftMC = -10 + (0.5 x 20) = 0 kip-ftSimilar to member 1, the value of moment in member 3 at joint C = 0As joint D is roller support, the value of moment at point D = 0 kip-ft