moment diagrama. A 265KN A = 135 kNm 5 kN 4m 3m eğn (35kNm tasskn
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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find the reactions. Write the equations. Use decimals.Fill in the blanks. Draw the shear and bending moment diagrams
![**Understanding Shear Force and Bending Moment Diagrams**
The provided image details the process of calculating shear force and bending moment diagrams for a beam subjected to a combination of point and distributed loads. Below is a transcription and explanation of the key components shown in the image.
**Diagrams:**
1. **Beam Load Diagram:**
- **Beam Support:** The beam is fixed at one end (A).
- **Loads:**
- A point load of \( 12 \mathrm{kN} \) is applied 1 meter from the support A.
- A uniformly distributed load (UDL) of \( 5 \mathrm{kN/m} \) is applied over the length of 3 meters starting from the point 4 meters from support A.
- **Dimensions:** The total length of the beam is shown in two segments, 4 meters and 3 meters, for a total of 7 meters.
2. **Triangular Load Equivalent:**
- A triangular load is indicated equivalent to the UDL.
- The calculation shows the total load due to this triangular load as the area under the load curve: \( (\frac{1}{2} \times 7 \times 5 = 35 \mathrm{kN}) \).
- The centroid of the triangular load acts at \( \frac{1}{3} \) from the larger end, shown with the moment arm calculations.
3. **Effective Shear Force and Bending Moment Equations:**
- **Notations:**
- \( \bar{q}_{eq1} = \) symbol representing the equivalent distributed load.
- \( \bar{V}_{eq1} = \) symbol representing the equivalent shear force.
- \( \bar{M}_{eq1} = \) symbol representing the equivalent bending moment.
4. **Shear Force Diagram (SFD):**
- No detailed values are indicated, but the general shape of the SFD is drawn with segments.
5. **Bending Moment Diagram (BMD):**
- Likewise, the general shape of the BMD is shown with indicated segments.
**Key Calculations:**
- The moment and force values indicated:
- \( A_{\mathrm{s}} = \frac{265}{kN \cdot m} \)
- \( A_{M} = \frac{135}{kN \cdot m} \)
-](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fed7b56a3-2e66-4877-848b-86d54658cb11%2Fca45bd8e-7186-415f-9164-516c970dc0a0%2F5q0jgk_processed.png&w=3840&q=75)
Transcribed Image Text:**Understanding Shear Force and Bending Moment Diagrams**
The provided image details the process of calculating shear force and bending moment diagrams for a beam subjected to a combination of point and distributed loads. Below is a transcription and explanation of the key components shown in the image.
**Diagrams:**
1. **Beam Load Diagram:**
- **Beam Support:** The beam is fixed at one end (A).
- **Loads:**
- A point load of \( 12 \mathrm{kN} \) is applied 1 meter from the support A.
- A uniformly distributed load (UDL) of \( 5 \mathrm{kN/m} \) is applied over the length of 3 meters starting from the point 4 meters from support A.
- **Dimensions:** The total length of the beam is shown in two segments, 4 meters and 3 meters, for a total of 7 meters.
2. **Triangular Load Equivalent:**
- A triangular load is indicated equivalent to the UDL.
- The calculation shows the total load due to this triangular load as the area under the load curve: \( (\frac{1}{2} \times 7 \times 5 = 35 \mathrm{kN}) \).
- The centroid of the triangular load acts at \( \frac{1}{3} \) from the larger end, shown with the moment arm calculations.
3. **Effective Shear Force and Bending Moment Equations:**
- **Notations:**
- \( \bar{q}_{eq1} = \) symbol representing the equivalent distributed load.
- \( \bar{V}_{eq1} = \) symbol representing the equivalent shear force.
- \( \bar{M}_{eq1} = \) symbol representing the equivalent bending moment.
4. **Shear Force Diagram (SFD):**
- No detailed values are indicated, but the general shape of the SFD is drawn with segments.
5. **Bending Moment Diagram (BMD):**
- Likewise, the general shape of the BMD is shown with indicated segments.
**Key Calculations:**
- The moment and force values indicated:
- \( A_{\mathrm{s}} = \frac{265}{kN \cdot m} \)
- \( A_{M} = \frac{135}{kN \cdot m} \)
-
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