Molybdenum has a work function of 4.20 eV. Find the cutoff frequency for the photoelectric effect.
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Q: Molybdenum has a work function of 4.20 eV. Find the cutoff wavelength for the photoelectric effect.
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- The work function of a material is found to be 4 eV. Electromagnetic radiation of frequency 6.8* 10 ^ 15 * Hz falls on it. What is the required potential to stop the photoelectrons?Light of wavelength 350 nm falls on a potassium surface, and the photoelectrons have amaximum kinetic energy of 1.3 eV.What is the work function of potassium?The speed of light is 3 × 108 m/s and Planck’sconstant is 6.63 × 10−34 J · s.Answer in units of eV. What is the threshold frequency for potassium?Answer in units of Hz.Lithium has a work function of 2.51 eV. What is the maximum kinetic energy of the photoelectrons if 9.7 x 10¹4 Hz radiation is incident upon it?
- The wavelength of a red spectral emission line is 670.0 nm. At what kinetic energy (in J) would an electron have that wavelength as its de Broglie wavelength?The work function of caesium metal is 2.14 eV. When light of frequency 6 x 1014 Hz is incident on the metal surface, photoemission of electrons occurs. What is the maximum kinetic energy of the emitted electrons,Light with a frequency of (1.99x10^15) Hz hits a metal with a work function of (4.200x10^0) eV. Determine the maximum velocity of photoelectrons generated by this setup.