Molly inflates a beach ball to a volume of 8 liters in her air-conditioned house where the temperature is 19 °C. Later that day, Molly takes the beach ball to the beach with some friends. The temperature at the beach was 33 °C, and the air pressure at the beach is the same as it was at the house. What will happen to Molly′s beach ball when she is at the beach?First, solve the problem EXACTLY like the example attached. Apply to the significant figure rule to your final answer. The final answer should have one significant figure.On taking the beach ball to the beach where the temperature is high, the ball will expand. Charles Law can be used to verify this because the pressure inside the beach ball is constant. V1=8.0 L, T1=19 °C, T2= 33 °C. For our Celsius numbers, we must convert them to Kelvin. The temperature can be converted from Celsius to Kelvin just by adding the number 273 to it. T1= (19 °C+273) K, T1= 292 K. T2= (33 °C+273) =, T2=306 K. According to Charles Law, V2/T2=V1/T1. Therefore, V2/306 K=8.0 L/292 K, V2=8.0 L/292 K*306 L. So, V2= 8.4 L. Since, the volume of the beach ball has increased from 8.0 L to 8.4 L it is fair to say that the beach ball has expanded. When the temperature of the object containing gas increases, it has to expand so the pressure is kept constant. Connect the claim and evidence with reasoning [the name and concept of the gas law you applied to solve the problem / answer the question and why did you choose to apply this gas law? #1 A sample of gas has a volume of 852 mL at 25 °C.You need to determine the Celsius temperature necessary for the gas to have a volume of 945 ml.V2=945 ml.T1 = 25 C (+ 273 = 298 K)T2 = ?1.2.Identify givens and the unknown.Convert all temperatures to Kelvin.3. Rearrange the equation if you'd like.4. Substitute values into the equation.5. Solve for the unknown.6. Check your answer against theory.V₁ = V₂SF12 converted back to Celsius:330 K 273 K = 57 CТ1 Т2V₁At 189 K, a sample of gas has a volume of 32.0 cm³.You need to determine the volume occupied bythe gas once it is heated to 242 K.таANSWER CHECK LINK:VI-32.0 cm^3V2=T1=189 KT2=242 KCD32.0 cm^3189 KP242 KV2*189 K=32.0 cm^3*242 KV2-189 K-7744 cm^3-K189 K18,9 K852 mL298 K12*852 mL = 298 K*945 mal852 ml.945. mi=41.0 cm^3T2 = 330 K » Significant Figure Rules01 >>All manzere digits are significant.Zeres that appear between otherHOMZETA digits are always significant.Zeros that appear in front of all of thenonzero daits are called left-end zeros.Left-end zeros are never significant.Zeros that appear after all nonzerodigits are called right-end zeros.à decimal point are not significant.Right-end zeros in a number with aThis is true whether the seres occurbefore or after the decimal point.337 has three significant figures.1.897 has four significant figures.39,004 has five significant figures.5.02 has three significant figures.0.008 has one significant figure.0.000416 has three significant figures.140 has two significant figures.75,310 has four significant figures.620.0 has four significant figures.19.000 has five significant figures.For multiplication and division problems, the answer should berounded to the same number of significant figures as themeasurement with the least number of significant figures.For addition and subtraction problems, the answer should berounded to the same number of decimal places as themeasurement with the least number of decimal places1

Charles law states that at constant pressure, the volume occupied by a fixed amount of gas is…

Molly inflates a beach ball to a volume of 8 liters in her air-conditioned house where the temperature is 19 °C. Later that day, Molly takes the beach ball to the beach with some friends. The temperature at the beach was 33 °C, and the air pressure at the beach is the same as it was at the house. What will happen to Molly′s beach ball when she is at the beach? First, solve the problem EXACTLY like the example attached. Apply to the significant figure rule to your final answer. The final answer should have one significant figure. On taking the beach ball to the beach where the temperature is high, the ball will expand. Charles Law can be used to verify this because the pressure inside the beach ball is constant. V1=8.0 L, T1=19 °C, T2= 33 °C. For our Celsius numbers, we must convert them to Kelvin. The temperature can be converted from Celsius to Kelvin just by adding the number 273 to it. T1= (19 °C+273) K, T1= 292 K. T2= (33 °C+273) =, T2=306 K. According to Charles Law, V2/T2=V1/T1. Therefore, V2/306 K=8.0 L/292 K, V2=8.0 L/292 K*306 L. So, V2= 8.4 L. Since, the volume of the beach ball has increased from 8.0 L to 8.4 L it is fair to say that the beach ball has expanded. When the temperature of the object containing gas increases, it has to expand so the pressure is kept constant. Connect the claim and evidence with reasoning [the name and concept of the gas law you applied to solve the problem / answer the question and why did you choose to apply this gas law?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Molly inflates a beach ball to a volume of 8 liters in her air-conditioned house where the temperature is 19 °C. Later that day, Molly takes the beach ball to the beach with some friends. The temperature at the beach was 33 °C, and the air pressure at the beach is the same as it was at the house. What will happen to Molly′s beach ball when she is at the beach?

First, solve the problem EXACTLY like the example attached. Apply to the significant figure rule to your final answer. The final answer should have one significant figure.

On taking the beach ball to the beach where the temperature is high, the ball will expand. Charles Law can be used to verify this because the pressure inside the beach ball is constant. V1=8.0 L, T1=19 °C, T2= 33 °C. For our Celsius numbers, we must convert them to Kelvin. The temperature can be converted from Celsius to Kelvin just by adding the number 273 to it. T1= (19 °C+273) K, T1= 292 K. T2= (33 °C+273) =, T2=306 K. According to Charles Law, V2/T2=V1/T1. Therefore, V2/306 K=8.0 L/292 K, V2=8.0 L/292 K*306 L. So, V2= 8.4 L. Since, the volume of the beach ball has increased from 8.0 L to 8.4 L it is fair to say that the beach ball has expanded. When the temperature of the object containing gas increases, it has to expand so the pressure is kept constant.

Connect the claim and evidence with reasoning [the name and concept of the gas law you applied to solve the problem / answer the question and why did you choose to apply this gas law?

#1 A sample of gas has a volume of 852 mL at 25 °C.
You need to determine the Celsius temperature necessary for the gas to have a volume of 945 ml.
V2=945 ml.
T1 = 25 C (+ 273 = 298 K)
T2 = ?
1.
2.
Identify givens and the unknown.
Convert all temperatures to Kelvin.
3. Rearrange the equation if you'd like.
4. Substitute values into the equation.
5. Solve for the unknown.
6. Check your answer against theory.
V₁ = V₂
SF
12 converted back to Celsius:
330 K 273 K = 57 C
Т1 Т2
V₁
At 189 K, a sample of gas has a volume of 32.0 cm³.
You need to determine the volume occupied by
the gas once it is heated to 242 K.
та
ANSWER CHECK LINK:
VI-32.0 cm^3
V2=
T1=189 K
T2=242 K
CD
32.0 cm^3
189 K
P
242 K
V2*189 K=32.0 cm^3*242 K
V2-189 K-7744 cm^3-K
189 K
18,9 K
852 mL
298 K
12*852 mL = 298 K*945 mal
852 ml.
945. mi
=41.0 cm^3
T2 = 330 K

» Significant Figure Rules
01 >>
All manzere digits are significant.
Zeres that appear between other
HOMZETA digits are always significant.
Zeros that appear in front of all of the
nonzero daits are called left-end zeros.
Left-end zeros are never significant.
Zeros that appear after all nonzero
digits are called right-end zeros.
à decimal point are not significant.
Right-end zeros in a number with a
This is true whether the seres occur
before or after the decimal point.
337 has three significant figures.
1.897 has four significant figures.
39,004 has five significant figures.
5.02 has three significant figures.
0.008 has one significant figure.
0.000416 has three significant figures.
140 has two significant figures.
75,310 has four significant figures.
620.0 has four significant figures.
19.000 has five significant figures.
For multiplication and division problems, the answer should be
rounded to the same number of significant figures as the
measurement with the least number of significant figures.
For addition and subtraction problems, the answer should be
rounded to the same number of decimal places as the
measurement with the least number of decimal places
1

Definition Definition Any of various laws that describe the ways in which volume, temperature, pressure, and other conditions correlate when matter is in a gaseous state. At a constant temperature, the pressure of a particular amount of gas is inversely proportional with its volume (Boyle's Law) In a closed system with constant pressure, the volume of an ideal gas is in direct relation with its temperature (Charles's Law) At a constant volume, the pressure of a gas is in direct relation to its temperature (Gay-Lussac's Law) If the volume of all gases are equal and under the a similar temperature and pressure, then they contain an equal number of molecules (Avogadro's Law) The state of a particular amount of gas can be determined by its pressure, volume and temperature (Ideal Gas law)

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