None mol7.8084× 0.4 L=molL20.93 cm x 4.125 cm=cmm850.9 m 0.75 s=SхлоX

For clear computation, please refer to this:This is solved using calculator. Answers presented are…

Answered: mol 7.8084 × 0.4 L = mol L 2 0.93 cm x…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Name these organic compounds: Η H H H | | | Η· C C C C C=H | | | | | H H H H H — H Η structure — — H H - C C 1 1 Η - Η - - Η - H | H — C - Η | H name
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6. _(6a)_ 2CUSO4. + 4NaOH » CH:COOH ±_(6b)__ + 2NA2SO4 + HzO
Use and modify some/all the reactions provided to form the indicated overall reaction according to Hess' Law. • If a reaction is not used in your Hess' Law process, include that indication by multiplying the reaction by "0" • If no modification is needed and the reaction is applied as written below, include that indication by multiplying the reaction by "1" • Use whole numbers and simple fractions (such as "2" or "1/2", not 0.5) and negative signs (such as "-2") where needed Then calculate and report the enthalpy change (in kJ) for the overall reaction in the indicated blank, including units with your written value and rounded to 1 decimal place. Overall Reaction: CS2(1) + 302(g) → CO2(g) + 2SO2(g) Rxn # Reaction ΔΗ° (kJ) 1 C(s) → C(g) 716.67 2 C(s) + O2(g) → CO2(g) -393.5 3 3Fe(s) +202(g) → Fe3O4(s) -1118 4 C(s) + 2S(s) → CS2(1) 87.9 5 CH4(g) + O2(g) → CO₂(g) + H₂O(g) -882.0 6 S(s) + O2(g) → SO2(g) -296.8 N2(g) + 4H2(g) + Cl2(g) → 2NH4Cl(g) -629.1 7
With the information provided answer C
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Given the following reactions Fe203(s) + 3CO(s) 2Fe(s) + 3CO2(g) AH = -28.0 kJ AH = +12.5 kJ 3Fe(s) + 4CO2(s) → 4CO2(g) + Fe3O4(s) + CO(g) → CO3(g) + 2FE3O4(s)- + 2FE304(s)' Determine the enthalpy of the reaction of Fe203 with CO: 3FE2O3(s) Answer:
Please help !!
Is there a reason those sig figs are wrong or are my calculations just completely off?

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mol 7.8084 × 0.4 L = mol L 2 0.93 cm x 4.125 cm = cm m 850.9 m 0.75 s = S хло X