-Modify this program to ask the enter the employees' information in order of last name, first name, number of hours, hourly rate, and if they are a cyber sec or computer sci major or both -To ask the user to enter the info, ask "Enter the info of ten employees as shown: Last Name, First Name, # of hours worked, hourly rate and if they are a cyber sec or computer sci major or both" -Have the calculations and amount the same as shown in the program and have it printed to the terminal and in the employee.txt file -The calculations should be the hours x # of hours worked, plus 1000 if they are a cyber sec or computer sci major and 2000 if they are both. -An example of the output is in the images #include using namespace std; struct Employee { string firstName; string lastName; int numOfHours; float hourlyRate; char major[2]; float amount; Employee* next; }; void printRecord(Employee*); void appendNode(Employee*&, Employee*); int main() { const int NumOfEmp = 10; Employee* head = nullptr; Employee* newNode; string firstNames[] = {"John", "Jane", "Mary", "Mike", "Sarah", "David", "Emily", "Alex", "Ethan", "Olivia"}; string lastNames[] = {"Smith", "Johnson", "Williams", "Jones", "Brown", "Garcia", "Miller", "Davis", "Rodriguez", "Martinez"}; int numOfHours[] = {40, 35, 42, 37, 39, 41, 38, 36, 43, 34}; float hourlyRate[] = {20.0, 22.5, 21.0, 22.0, 20.5, 23.0, 22.0, 21.5, 23.5, 20.0}; char comp_sci[] = {'Y', 'N', 'Y', 'Y', 'N', 'Y', 'N', 'Y', 'N', 'Y'}; char comp_sec[] = {'N', 'N', 'Y', 'Y', 'Y', 'N', 'Y', 'Y', 'N', 'N'}; cout<firstName = firstNames[i]; newNode->lastName = lastNames[i]; newNode->numOfHours = numOfHours[i]; newNode->hourlyRate = hourlyRate[i]; newNode->major[0] = comp_sci[i]; newNode->major[1] = comp_sec[i]; newNode->amount = newNode->numOfHours * newNode->hourlyRate; if (newNode->major[0] == 'Y' || newNode->major[1] == 'Y') { newNode->amount = newNode->amount + 1000; } if (newNode->major[0] == 'Y' && newNode->major[1] == 'Y') { newNode->amount = newNode->amount + 2000; } newNode->next = nullptr; appendNode(head, newNode); printRecord(newNode); } ofstream outfile("Employee.txt"); if (!outfile) { cerr << "Error: Output file could not be opened." << endl; return 1; } outfile<lastName << setw(15) << current->firstName << setw(12) << current->numOfHours << setw(20) << current->hourlyRate << setw(20) << current->amount << setw(20) << current->major[0]<major[1] << endl; current = current->next; } outfile.close(); return 0; } void printRecord(Employee* e) { cout << left << setw(15) << e->lastName << setw(15) << e->firstName << setw(12) <numOfHours<hourlyRate<amount << setw(10) << e->major[0] << setw(10) << e->major[1]<< endl; } void appendNode(Employee*& head, Employee* newNode) { if (head == nullptr) { head = newNode; } else { Employee* current = head; while (current->next != nullptr) { current = current->next; } current->next = newNode; } }

-Modify this program to ask the enter the employees' information in order of last name, first name, number of hours, hourly rate, and if they are a cyber sec or computer sci major or both -To ask the user to enter the info, ask "Enter the info of ten employees as shown: Last Name, First Name, # of hours worked, hourly rate and if they are a cyber sec or computer sci major or both" -Have the calculations and amount the same as shown in the program and have it printed to the terminal and in the employee.txt file -The calculations should be the hours x # of hours worked, plus 1000 if they are a cyber sec or computer sci major and 2000 if they are both. -An example of the output is in the images #include using namespace std; struct Employee { string firstName; string lastName; int numOfHours; float hourlyRate; char major[2]; float amount; Employee* next; }; void printRecord(Employee); void appendNode(Employee&, Employee); int main() { const int NumOfEmp = 10; Employee head = nullptr; Employee* newNode; string firstNames[] = {"John", "Jane", "Mary", "Mike", "Sarah", "David", "Emily", "Alex", "Ethan", "Olivia"}; string lastNames[] = {"Smith", "Johnson", "Williams", "Jones", "Brown", "Garcia", "Miller", "Davis", "Rodriguez", "Martinez"}; int numOfHours[] = {40, 35, 42, 37, 39, 41, 38, 36, 43, 34}; float hourlyRate[] = {20.0, 22.5, 21.0, 22.0, 20.5, 23.0, 22.0, 21.5, 23.5, 20.0}; char comp_sci[] = {'Y', 'N', 'Y', 'Y', 'N', 'Y', 'N', 'Y', 'N', 'Y'}; char comp_sec[] = {'N', 'N', 'Y', 'Y', 'Y', 'N', 'Y', 'Y', 'N', 'N'}; cout<firstName = firstNames[i]; newNode->lastName = lastNames[i]; newNode->numOfHours = numOfHours[i]; newNode->hourlyRate = hourlyRate[i]; newNode->major[0] = comp_sci[i]; newNode->major[1] = comp_sec[i]; newNode->amount = newNode->numOfHours * newNode->hourlyRate; if (newNode->major[0] == 'Y' || newNode->major[1] == 'Y') { newNode->amount = newNode->amount + 1000; } if (newNode->major[0] == 'Y' && newNode->major[1] == 'Y') { newNode->amount = newNode->amount + 2000; } newNode->next = nullptr; appendNode(head, newNode); printRecord(newNode); } ofstream outfile("Employee.txt"); if (!outfile) { cerr << "Error: Output file could not be opened." << endl; return 1; } outfile<lastName << setw(15) << current->firstName << setw(12) << current->numOfHours << setw(20) << current->hourlyRate << setw(20) << current->amount << setw(20) << current->major[0]<major[1] << endl; current = current->next; } outfile.close(); return 0; } void printRecord(Employee* e) { cout << left << setw(15) << e->lastName << setw(15) << e->firstName << setw(12) <numOfHours<hourlyRate<amount << setw(10) << e->major[0] << setw(10) << e->major[1]<< endl; } void appendNode(Employee& head, Employee newNode) { if (head == nullptr) { head = newNode; } else { Employee* current = head; while (current->next != nullptr) { current = current->next; } current->next = newNode; } }

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

-Modify this program to ask the enter the employees' information in order of last name, first name, number of hours, hourly rate, and if they are a cyber sec or computer sci major or both

-To ask the user to enter the info, ask

"Enter the info of ten employees as shown: Last Name, First Name, # of hours worked, hourly rate and if they are a cyber sec or computer sci major or both"

-Have the calculations and amount the same as shown in the program and have it printed to the terminal and in the employee.txt file

-The calculations should be the hours x # of hours worked, plus 1000 if they are a cyber sec or computer sci major and 2000 if they are both.

-An example of the output is in the images

#include<bits/stdc++.h>

using namespace std;

struct Employee {

string firstName;

string lastName;

int numOfHours;

float hourlyRate;

char major[2];

float amount;

Employee* next;

};

void printRecord(Employee*);

void appendNode(Employee*&, Employee*);

int main() {

const int NumOfEmp = 10;

Employee* head = nullptr;

Employee* newNode;

string firstNames[] = {"John", "Jane", "Mary", "Mike", "Sarah", "David", "Emily", "Alex", "Ethan", "Olivia"};

string lastNames[] = {"Smith", "Johnson", "Williams", "Jones", "Brown", "Garcia", "Miller", "Davis", "Rodriguez", "Martinez"};

int numOfHours[] = {40, 35, 42, 37, 39, 41, 38, 36, 43, 34};

float hourlyRate[] = {20.0, 22.5, 21.0, 22.0, 20.5, 23.0, 22.0, 21.5, 23.5, 20.0};

char comp_sci[] = {'Y', 'N', 'Y', 'Y', 'N', 'Y', 'N', 'Y', 'N', 'Y'};

char comp_sec[] = {'N', 'N', 'Y', 'Y', 'Y', 'N', 'Y', 'Y', 'N', 'N'};

cout<<left<<setw(15) <<"Last Name"<<setw(15) <<"First Name"<<setw(12) <<"# of Hours"<<setw(12) <<"Hourly Rate"

<< setw(10) << "Amount"<< setw(10)<<"Comp Sci" << setw(20) << "Comp Sec" << endl;

for (int i = 0; i < NumOfEmp; i++) {

newNode = new Employee;

newNode->firstName = firstNames[i];

newNode->lastName = lastNames[i];

newNode->numOfHours = numOfHours[i];

newNode->hourlyRate = hourlyRate[i];

newNode->major[0] = comp_sci[i];

newNode->major[1] = comp_sec[i];

newNode->amount = newNode->numOfHours * newNode->hourlyRate;

if (newNode->major[0] == 'Y' || newNode->major[1] == 'Y') {

newNode->amount = newNode->amount + 1000;

}

if (newNode->major[0] == 'Y' && newNode->major[1] == 'Y') {

newNode->amount = newNode->amount + 2000;

}

newNode->next = nullptr;

appendNode(head, newNode);

printRecord(newNode);

}

ofstream outfile("Employee.txt");

if (!outfile) {

cerr << "Error: Output file could not be opened." << endl;

return 1;

}

outfile<<left<<setw(15) <<"Last Name"<<setw(15) <<"First Name"<<setw(12) <<"# of Hours"<<setw(20) <<"Hourly Rate"

<< setw(20) << "Amount"<< setw(20)<<"Comp Sci" << setw(20) << "Comp Sec" << endl;

Employee* current = head;

while (current != nullptr) {

outfile << left << setw(15) << current->lastName << setw(15) << current->firstName << setw(12) << current->numOfHours << setw(20)

<< current->hourlyRate << setw(20) << current->amount << setw(20) << current->major[0]<<setw(25)<< setw(25) << current->major[1] << endl;

current = current->next;

}

outfile.close();

return 0;

}

void printRecord(Employee* e) {

cout << left << setw(15) << e->lastName << setw(15) << e->firstName << setw(12)

<<e->numOfHours<<setw(12) <<e->hourlyRate<<setw(10) <<e->amount

<< setw(10) << e->major[0] << setw(10) << e->major[1]<< endl;

}

void appendNode(Employee*& head, Employee* newNode) {

if (head == nullptr) {

head = newNode;

}

else {

Employee* current = head;

while (current->next != nullptr) {

current = current->next;

}

current->next = newNode;

}

main.cpp
1 Last Name
2 Smith
3 Johnson
4 Williams
5 Jones
6 Brown
7 Garcia
8 Miller
9 Davis
10 Rodriguez
11 Martinez
12
Smith
Johnson
Williams
Run ✪ Debug
Employee.txt:
Jones
Brown
Garcia
Miller
Davis
Rodriguez
Martinez
John
Jane
Mary
Mike
Sarah
David
Emily
Alex
Mary
Mike
■ Stop
First Name
John
Jane
Ethan
olivia
Sarah
David
Emily
Alex
Ethan
Olivia
40
35
42
37
39
41
38
36
43
34
Share
. Program finished with exit code 0
39
41
H Save
# of Hours Hourly Rate
40
35
42
37
38
36
43
34
20
22.5
21
22
20.5
23
22
{} Beautify
21.5
23.5
20
20
22.5
21
22
20.5
23
22
21.5
23.5
20
800
787.5
882
814
799.5
943
836
774
1010.5
680
Y
MHMARHAMAD
N
Y
Y
N
Y
N
Y
N
Y
Amount
800
787.5
882
814
799.5
943
836
774
1010.5
680
input
NNNNNNNNNN
Y
Y
Y
Y
Y
Comp Sci
Y
> > > > > > > > > >
N
Y
Y
N
Y
N
Y
N
Y
Language C++
Comp Sec
N
N
Y
Y
Y
Y
Y
N
N

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