Modify the existing vector's contents, by erasing the element at index 1 (initially 200), then inserting 100 and 102 in the shownlocations. Use Vector ADT's erase() and insert() only, and remember that the first argument of those functions is special, involvingan iterator and not just an integer. Sample output of below program with input 33 200 10:100 33 102 10Learn how our autograder works464730.3214874.qx3zay712 }1314 int main() {15vector numsList;int user Input;int i;161718192021222223242526CS Scanneru2829 }for (i = 0; i < 3; ++i) {cin >> user Input;numsList.push_back(user Input);}V* Your solution goes here */Print Vectors (numslist);return 6;1 testpassedAll testspassed CSModify the existing vector's contents, by erasing the element at index 1 (initially 200), then inserting 100 and 102 in the shownlocations. Use Vector ADT's erase() and insert() only, and remember that the first argument of those functions is special, involvingan iterator and not just an integer. Sample output of below program with input 33 200 10:100 33 102 10Learn how our autograder works4647303214874 qx3zqy?1 #include 2 #include 3 using namespace std;5 void Print Vectors (vector numsList) {unsigned int i;101112 }1718for (i = 0; i < numsList.size(); ++i) {cout << numsList.at(i) << " ";1314 int main() {1516can}cout << endl;vector numsList;int user Input;int i;with CamScannerDO1 testpassedAll testspassedFeedback?

Include the necessary libraries - iostream and vector. Use the standard namespace using "using…

Modify the existing vector's contents, by erasing the element at index 1 (initially 200), then inserting 100 and 102 in the shown locations. Use Vector ADT's erase() and insert() only, and remember that the first argument of those functions is special, involving an iterator and not just an integer. Sample output of below program with input 33 200 10: 100 33 102 10 Learn how our autograder works -4647303214874.qx3zay7 12 } 13 14 int main() { 15 16 17 17 18 18 19 19 20 21 21 22 22 23 24 25 vector numsList; int user Input; int i; for (i = 0; i < 3; ++i) { cin >> user Input; numsList.push_back(user Input); } V* Your solution goes here */ 26 Scanner 29 } Print Vectors (numslist); return 6; sustaimScanner

Modify the existing vector's contents, by erasing the element at index 1 (initially 200), then inserting 100 and 102 in the shown locations. Use Vector ADT's erase() and insert() only, and remember that the first argument of those functions is special, involving an iterator and not just an integer. Sample output of below program with input 33 200 10: 100 33 102 10 Learn how our autograder works -4647303214874.qx3zay7 12 } 13 14 int main() { 15 16 17 17 18 18 19 19 20 21 21 22 22 23 24 25 vector numsList; int user Input; int i; for (i = 0; i < 3; ++i) { cin >> user Input; numsList.push_back(user Input); } V* Your solution goes here */ 26 Scanner 29 } Print Vectors (numslist); return 6; sustaimScanner

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Develop an implementation of insertion sortthat moves larger elements to the right one position with one array access per entry,rather than using exch(). Use SortCompare to evaluate the effectiveness of doing so.Develop an implementation of insertion sortthat moves larger elements to the right one position with one array access per entry,rather than using exch(). Use SortCompare to evaluate the effectiveness of doing so.
e.g., Tam 180 cm tall." am (your Q2 (Intro to R+ Functions + If statements + Loops) Question: Divisibility by 3 Q2 (a): Create a new vector: x = c(1:100), and find which elements of x is completely divisible by 3 Q2 (b): Create a function 'divisibility_3' that takes a number as the argument, and checks if the number is completely divisible by 3. If so, get an output that prints: "(the input number) is divisible by 3". Otherwise, get an output that prints: " (the input number) is not divisible by 3" e.g., divisibility_3(100) "100 is not divisible by 3" e.g., divisibility_3(99) "99 is divisible by 3" Q2 (c): Create a function 'count_divisibility_3' that takes a vector as the argument, and return the total number of elements that is completely divisible by 3. e.g., count_divisibility_3(c(1,2,3,4,5,6,7,8,9)) 3 count_divisibility_3(c(1:200)) 66 e.g., Q3 (Intro to R+ If statements + Functions) Q3: Create a function 'absolute_value' that takes a number as the argument, and returns the…
MATLAB: Create a vector named n which starts at -10 and steps by 1 to end at +10 by using the start:step:stop syntax. Next, generate a vector x1 so that x1 satisfies the mathematical relationship ?ଵ[?]=(0.60). Since n is a vector, one will need to utilize 0.60.^n (i.e., .^ is used in place of ^) to define x1. Redo the work just completed, but for a vector x2 where x2 satisfies the mathematical relationship ?ଶ[?]=(0.85). Repeat the work just completed, but for a vector x3 where x3 satisfies the mathematical relationship ?ଷ[?]=(1.10). In one figure window, plot x1 as a function of n using the stem command. The stem plot must show BLACK (versus the default blue) lines that have filled circles and a line width of 2; refer to the lecture example script file. Further, the horizontal axis label (xlabel) must be n, the title (title) must include your name and the vertical axis label (ylabel) must show ?ଵ[?]=(0.60)(note the subscript and superscript). In addition, turn on the grid (doc grid),…
I'm trying to create two functions where each calculates a cube. One that uses numpy and uses function power and can't use for loops. Other uses a range of intergers and returns a list of each range elements using pow. I can get each to cube but I can't figure out how to do it by defining a function. import numpy as nparray1 = np.array([3,5,10,9]) cubedarray1 = np.power(array1, 3)print('This is the cubed arrray 1: ', cubedarray1)array2 = range(1,10,2) # range is 1, 3, 5, 7, 9cubedarray2 = [pow(i, 3) for i in array2]print('This is the cubed array 2: ', cubedarray2)
Write a similarprogram to compare two vectors. we should make 6 test : same length the first is longer, the second is longer, equal, the first greater , the second greater; try different symbols not only letters
Write aJava function given an array of integers nums [passed by reference] and an integer target, return indices of the two numbers such that they add up to target. You may assume that each input would have exactly one solution, and you may not use the same element twice. You can return the answer in any order.
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