* mode (20) * mean A 20 1+ 3 + 5+ 6+ 7+10 = 6 *medica = n+l 2 - E 5,3 5+6 2 = 1,3,5,6,7,10 5,5
* mode (20) * mean A 20 1+ 3 + 5+ 6+ 7+10 = 6 *medica = n+l 2 - E 5,3 5+6 2 = 1,3,5,6,7,10 5,5
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![**Class Interval Frequency Table:**
| Class Interval | Frequency (f) | \( x - \bar{x} \) | \( (x - \bar{x})^2 \) |
|----------------|--------------|--------------------|----------------------|
| 10-20 | 1 | | |
| 20-30 | 3 | | |
| 30-40 | 5 | | |
| 40-50 | 7 | | |
| 50-60 | 10 | | |
| 60-70 | 6 | | |
\[ \sum f = 32 \]
**Central Tendency Calculations:**
- **Mode**: The mode is the value that appears most frequently in a data set. Here, it is 20. The graph shows a peak at this value, indicating the mode.
- **Mean**: The mean is calculated as follows:
\[
\text{Mean} = \frac{1 + 3 + 5 + 6 + 7 + 10}{6} = 5.3
\]
- **Median**: The median is the middle value when the data is ordered. It is calculated as:
\[
\text{Median} = \frac{n+1}{2} = \frac{5+6}{2} = 5.5
\]
- **First Quartile (\( Q_1 \))**: This is the median of the first half of the data and is calculated as:
\[
Q_1 = \frac{1}{4} (n+1) = \frac{1}{4} (6+1) = 1.75
\]
- **Third Quartile (\( Q_3 \))**: This is the median of the second half of the data and is calculated as:
\[
Q_3 = \frac{3}{4} (n+1) = \frac{3}{4} (6+1) = 5.25
\]
**Graph Explanation:**
The graph depicted appears to be a simple representation showing the mode at 20 with a peak on the curve at this point.
The calculations above provide various measures of central tendency from a frequency distribution table, helping](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3e5571ee-5d6d-4f79-ad82-a411e490de76%2Fa1c7b500-7f99-4007-8afb-618fe41a2410%2F8nxzb2p_processed.png&w=3840&q=75)
Transcribed Image Text:**Class Interval Frequency Table:**
| Class Interval | Frequency (f) | \( x - \bar{x} \) | \( (x - \bar{x})^2 \) |
|----------------|--------------|--------------------|----------------------|
| 10-20 | 1 | | |
| 20-30 | 3 | | |
| 30-40 | 5 | | |
| 40-50 | 7 | | |
| 50-60 | 10 | | |
| 60-70 | 6 | | |
\[ \sum f = 32 \]
**Central Tendency Calculations:**
- **Mode**: The mode is the value that appears most frequently in a data set. Here, it is 20. The graph shows a peak at this value, indicating the mode.
- **Mean**: The mean is calculated as follows:
\[
\text{Mean} = \frac{1 + 3 + 5 + 6 + 7 + 10}{6} = 5.3
\]
- **Median**: The median is the middle value when the data is ordered. It is calculated as:
\[
\text{Median} = \frac{n+1}{2} = \frac{5+6}{2} = 5.5
\]
- **First Quartile (\( Q_1 \))**: This is the median of the first half of the data and is calculated as:
\[
Q_1 = \frac{1}{4} (n+1) = \frac{1}{4} (6+1) = 1.75
\]
- **Third Quartile (\( Q_3 \))**: This is the median of the second half of the data and is calculated as:
\[
Q_3 = \frac{3}{4} (n+1) = \frac{3}{4} (6+1) = 5.25
\]
**Graph Explanation:**
The graph depicted appears to be a simple representation showing the mode at 20 with a peak on the curve at this point.
The calculations above provide various measures of central tendency from a frequency distribution table, helping
Expert Solution
Step 1
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