**Class Interval Frequency Table:**| Class Interval | Frequency (f) | \( x - \bar{x} \) | \( (x - \bar{x})^2 \) ||----------------|--------------|--------------------|----------------------|| 10-20 | 1 | | || 20-30 | 3 | | || 30-40 | 5 | | || 40-50 | 7 | | || 50-60 | 10 | | || 60-70 | 6 | | |\[ \sum f = 32 \]**Central Tendency Calculations:**- **Mode**: The mode is the value that appears most frequently in a data set. Here, it is 20. The graph shows a peak at this value, indicating the mode.- **Mean**: The mean is calculated as follows: \[ \text{Mean} = \frac{1 + 3 + 5 + 6 + 7 + 10}{6} = 5.3 \]- **Median**: The median is the middle value when the data is ordered. It is calculated as: \[ \text{Median} = \frac{n+1}{2} = \frac{5+6}{2} = 5.5 \]- **First Quartile (\( Q_1 \))**: This is the median of the first half of the data and is calculated as: \[ Q_1 = \frac{1}{4} (n+1) = \frac{1}{4} (6+1) = 1.75 \]- **Third Quartile (\( Q_3 \))**: This is the median of the second half of the data and is calculated as: \[ Q_3 = \frac{3}{4} (n+1) = \frac{3}{4} (6+1) = 5.25 \]**Graph Explanation:**The graph depicted appears to be a simple representation showing the mode at 20 with a peak on the curve at this point.The calculations above provide various measures of central tendency from a frequency distribution table, helping

Answered: * mode (20) * mean A 20 1+ 3 + 5+ 6+…

* mode (20) * mean A 20 1+ 3 + 5+ 6+ 7+10 = 6 *medica = n+l 2 - E 5,3 5+6 2 = 1,3,5,6,7,10 5,5

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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