MO21. Many cardiac patients wear an implanted pacemaker to control their heartbeat. A plastic connector module mounts on the top of the pacemaker. Assuming a standard deviation of 0.0207 inch and an approximately normal distribution, find a 95% prediction interval for the mean of the depths of all connector modules to be made by a certain manufacturing company. A random sample of 77 modules has an average depth of 0.36 inch. Input the value the lower limit of the Prediction Interval in the blank provided up to 4 decimal places i.e., 0.0000. Provide all the necessary solutions in the submission for both upper and lower limit. Upper limit of the interval is Blank 1.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
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Chapter10: Statistics
Section10.4: Distributions Of Data
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MO21. Many cardiac patients wear an implanted pacemaker to control their heartbeat. A plastic connector module mounts on the top
of the pacemaker. Assuming a standard deviation of 0.0207 inch and an approximately normal distribution, find a 95% prediction
interval for the mean of the depths of all connector modules to be made by a certain manufacturing company. A random sample of 77
modules has an average depth of 0.36 inch. Input the value the lower limit of the Prediction Iriterval in the blank provided up to 4
decimal places i.e., 0.0000. Provide all the necessary solutions in the submission for both upper and lower limit.
Upper limit of the interval is Blank 1.
Blank 1
Add your answer
Transcribed Image Text:MO21. Many cardiac patients wear an implanted pacemaker to control their heartbeat. A plastic connector module mounts on the top of the pacemaker. Assuming a standard deviation of 0.0207 inch and an approximately normal distribution, find a 95% prediction interval for the mean of the depths of all connector modules to be made by a certain manufacturing company. A random sample of 77 modules has an average depth of 0.36 inch. Input the value the lower limit of the Prediction Iriterval in the blank provided up to 4 decimal places i.e., 0.0000. Provide all the necessary solutions in the submission for both upper and lower limit. Upper limit of the interval is Blank 1. Blank 1 Add your answer
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