MNSO4 · H20(aq) + H2C2O4(aq) +2H20() - Starting with 3.84 g of MNSO4 · H2O with an excess of oxalic acid, 2.50 g of MnC2O4• 3H2O is produced. Calculate the percent yield. MnC2O4• 3H2O(s) +H2SO4(aq) > The molar mass of MnSO4 · H2O is 169.01 g/mol and the molar mass of MnC2O4• 3H2O is 197.00 g/mol.
MNSO4 · H20(aq) + H2C2O4(aq) +2H20() - Starting with 3.84 g of MNSO4 · H2O with an excess of oxalic acid, 2.50 g of MnC2O4• 3H2O is produced. Calculate the percent yield. MnC2O4• 3H2O(s) +H2SO4(aq) > The molar mass of MnSO4 · H2O is 169.01 g/mol and the molar mass of MnC2O4• 3H2O is 197.00 g/mol.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:MNSO4 · H20(aq) + H2C2O4(aq) +2H2O()
MnC204. 3H2O(s) +H2SO4(aq)
Starting with 3.84 g of MNSO4 · H20 with an excess of oxalic acid, 2.50 g of MnC2O4. 3H2O is produced.
Calculate the percent yield.
The molar mass of MNSO4 · H2O is 169.01 g/mol and the molar mass of MnC2O4. 3H20 is 197.00 g/mol.
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