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mnps.schoology.com to search An inequality is solved as shown below. Between which two steps is an error made? Then explain the error. Step 1: -3(x+2) ≥ 8 Step 2: -3x+628 Step 3: -3x+6-628 Step 4: -3x+028-6 Step 5: -3x ≥ 8-6 Step 6: -3.x ≥ 2 Step 7: x=² Step 8: Step 9: 6 180 12 N HEALI 3 Between steps 5 and 6 Between steps and 2 Between steps 7 and 8 Between steps 3 and 4 Between steps 4 and 5 0 in 6

mnps.schoology.com to search An inequality is solved as shown below. Between which two steps is an error made? Then explain the error. Step 1: -3(x+2) ≥ 8 Step 2: -3x+628 Step 3: -3x+6-628 Step 4: -3x+028-6 Step 5: -3x ≥ 8-6 Step 6: -3.x ≥ 2 Step 7: x=² Step 8: Step 9: 6 180 12 N HEALI 3 Between steps 5 and 6 Between steps and 2 Between steps 7 and 8 Between steps 3 and 4 Between steps 4 and 5 0 in 6

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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**Problem Statement:** An inequality is solved as shown below. Between which two steps is an error made? Then explain the error. **Steps:** - **Step 1:** \(-3(x + 2) \geq 8\) - **Step 2:** \(-3x + 6 \geq 8\) - **Step 3:** \(-3x + 6 - 6 \geq 8 - 6\) - **Step 4:** \(-3x + 0 \geq 8 - 6\) - **Step 5:** \(-3x \geq 8 - 6\) - **Step 6:** \(-3x \geq 2\) - **Step 7:** \(\frac{-3x}{-3} \leq \frac{2}{-3}\) - **Step 8:** \(1x \leq -\frac{2}{3}\) - **Step 9:** \(x \leq -\frac{2}{3}\) **Options:** - a) Between steps 5 and 6 - b) Between steps 1 and 2 - c) Between steps 7 and 8 - d) Between steps 3 and 4 - e) Between steps 4 and 5 **Explanation:** An error is made between steps 6 and 7. When dividing or multiplying both sides of an inequality by a negative number, the direction of the inequality sign must be reversed. In step 7, the inequality sign should remain \(\geq\), not change to \(\leq\).
Transcribed Image Text:**Problem Statement:** An inequality is solved as shown below. Between which two steps is an error made? Then explain the error. **Steps:** - **Step 1:** \(-3(x + 2) \geq 8\) - **Step 2:** \(-3x + 6 \geq 8\) - **Step 3:** \(-3x + 6 - 6 \geq 8 - 6\) - **Step 4:** \(-3x + 0 \geq 8 - 6\) - **Step 5:** \(-3x \geq 8 - 6\) - **Step 6:** \(-3x \geq 2\) - **Step 7:** \(\frac{-3x}{-3} \leq \frac{2}{-3}\) - **Step 8:** \(1x \leq -\frac{2}{3}\) - **Step 9:** \(x \leq -\frac{2}{3}\) **Options:** - a) Between steps 5 and 6 - b) Between steps 1 and 2 - c) Between steps 7 and 8 - d) Between steps 3 and 4 - e) Between steps 4 and 5 **Explanation:** An error is made between steps 6 and 7. When dividing or multiplying both sides of an inequality by a negative number, the direction of the inequality sign must be reversed. In step 7, the inequality sign should remain \(\geq\), not change to \(\leq\).
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