MISSED THIS? Read Section 16.8 (Pages 701-710); Watch IWE 16.8. Consider the following reaction: Consider the reaction 2NO(g) + Br₂ (g) = 2NOBr(g), Kp = 28.4 at 298 K In a reaction mixture at equilibrium, the partial pressure of NO is 121 torr and that of Br₂ is 141 ↓ torr. Part A What is the partial pressure of NOBr in this mixture? Express your answer in torrs to three significant figures. ► View Available Hint(s) IVE ΑΣΦΑ PNOB = Submit ? torr

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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**Equilibrium Reaction Analysis**

**Reaction Details:**
- **Reaction:** \( \text{2NO(g) + Br}_2\text{(g)} \rightleftharpoons \text{2NOBr(g)} \)
- **Equilibrium Constant (\( K_p \))**: 28.4 at 298 K

**Given Partial Pressures at Equilibrium:**
- **\( \text{NO} \):** 121 torr
- **\( \text{Br}_2 \):** 141 torr

**Problem Statement:**
- **Part A:** Calculate the partial pressure of \( \text{NOBr} \) in the mixture at equilibrium.
  - **Answer Format:** Express your answer in torrs, rounded to three significant figures.

**Answer Submission:**
- **\( P_{\text{NOBr}} \):** [Input Box] torr

Click "Submit" to check your answer.

*Note: Please view available hints for assistance with the calculation process.*
Transcribed Image Text:**Equilibrium Reaction Analysis** **Reaction Details:** - **Reaction:** \( \text{2NO(g) + Br}_2\text{(g)} \rightleftharpoons \text{2NOBr(g)} \) - **Equilibrium Constant (\( K_p \))**: 28.4 at 298 K **Given Partial Pressures at Equilibrium:** - **\( \text{NO} \):** 121 torr - **\( \text{Br}_2 \):** 141 torr **Problem Statement:** - **Part A:** Calculate the partial pressure of \( \text{NOBr} \) in the mixture at equilibrium. - **Answer Format:** Express your answer in torrs, rounded to three significant figures. **Answer Submission:** - **\( P_{\text{NOBr}} \):** [Input Box] torr Click "Submit" to check your answer. *Note: Please view available hints for assistance with the calculation process.*
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