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Miss Johnson cuts out a triangular shape from her circular floor carpet as illustrated on the diagram. The dimensions are as follows: PQ is the diameter of the carpet, R 90°, Line RQ 3m, Line PR =10m %3D P Calculate: .2.1 The length of the diameter. HINT, You will no

Miss Johnson cuts out a triangular shape from her circular floor carpet as illustrated on the diagram. The dimensions are as follows: PQ is the diameter of the carpet, R 90°, Line RQ 3m, Line PR =10m %3D P Calculate: .2.1 The length of the diameter. HINT, You will no

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Miss Johnson cuts out a triangular shape from a circular floor carpet. The dimensions are as follows: PQ is the diameter of the carpet, R= 90degrees, Line RQ= 3m, Line PR= 10m. The length of the diameter
figure. 3.1.2 Calculate the area of the shape. Miss Johnson cuts out a triangular shape from her circular floor carpet as illustrated on the diagram. The dimensions are as follows: PQ is the diameter of the carpet, R 90°, Line RQ = 3m, Line PR 10m Calculate: .2.1 The length of the diameter. HINT. You will need the Theorem of Pythagoras. 2.2 The area of the triangle. 2.3 The radius of the circle. 2.4 The perimeter of the triangle. ed
Transcribed Image Text:figure. 3.1.2 Calculate the area of the shape. Miss Johnson cuts out a triangular shape from her circular floor carpet as illustrated on the diagram. The dimensions are as follows: PQ is the diameter of the carpet, R 90°, Line RQ = 3m, Line PR 10m Calculate: .2.1 The length of the diameter. HINT. You will need the Theorem of Pythagoras. 2.2 The area of the triangle. 2.3 The radius of the circle. 2.4 The perimeter of the triangle. ed
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