Minimize the following functions using Boolean algebra: a) F = A'B'.C.D' + A'.B.C.D+A'.B.C.D' + A.B.C.D' + A'B'.C.D' + A.B.C.D' + A'B'.C.D b) F = A'B'C' + A'B+ABC' + AC here' means inversion of the variable.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Minimize the following functions using Boolean algebra:

a) \( F = A'B'C'D' + A'BC'D + A'BC'D' + AB'C'D' + A'B'C'D + AB'CD' + AB'CD + A'B'CD' + A'B'C'D \)

b) \( F = A'B'C' + A'B'ABC' + AC \)

Here, \( ' \) means inversion of the variable.
Transcribed Image Text:Minimize the following functions using Boolean algebra: a) \( F = A'B'C'D' + A'BC'D + A'BC'D' + AB'C'D' + A'B'C'D + AB'CD' + AB'CD + A'B'CD' + A'B'C'D \) b) \( F = A'B'C' + A'B'ABC' + AC \) Here, \( ' \) means inversion of the variable.
Expert Solution
Step 1: Part1:

Certainly! Let's go through the minimization process for both functions :
a) F equals A to the power of prime. B to the power of prime. C to the power of prime. D to the power of prime plus A to the power of prime. B. C to the power of prime. D plus A to the power of prime. B. C to the power of prime. D to the power of prime plus A. B to the power of prime. C to the power of prime. D to the power of prime plus A to the power of prime. B to the power of prime. C. D to the power of prime plus A. B to the power of prime. C. D to the power of prime plus A to the power of prime B to the power of prime C to the power of prime. D

Group the terms and eliminate duplicates:

F equals A to the power of prime. B to the power of prime. C to the power of prime. D to the power of prime plus A to the power of prime. B. C to the power of prime. D plus A. B to the power of prime. C to the power of prime. D to the power of prime plus A to the power of prime. B to the power of prime. C. D to the power of prime plus A. B to the power of prime. C. D to the power of prime plus A to the power of prime B to the power of prime C to the power of prime. D

Apply the absorption law X plus X to the power of prime Y equals X plus Y:

F equals A to the power of prime. B. C to the power of prime. D plus A. B to the power of prime. C. D to the power of prime plus A to the power of prime B to the power of prime C to the power of prime. D

So, the minimized expression is:

F equals A to the power of prime. B. C to the power of prime. D plus A. B to the power of prime. C. D to the power of prime plus A to the power of prime B to the power of prime C to the power of prime. D


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