Millikan measured the electron's charge by observing tiny charged oil drops in an electric field. Each drop had a charge imbalance of only a few electrons. The strength of the electric field was adjusted so that the electric and gravitational forces on a drop would balance and the drop would be suspended in air. In this way the charge on the drop could be calculated. The charge was always found to be a small multiple of 1.6e-19 C. Find the charge on an oil drop weighing 1.94 10-14 N and suspended in a downward field of magnitude 2.42 104 N/C.
17 q9
Millikan measured the electron's charge by observing tiny charged oil drops in an electric field. Each drop had a charge imbalance of only a few electrons. The strength of the electric field was adjusted so that the electric and gravitational forces on a drop would balance and the drop would be suspended in air. In this way the charge on the drop could be calculated. The charge was always found to be a small multiple of 1.6e-19 C. Find the charge on an oil drop weighing 1.94 10-14 N and suspended in a downward field of magnitude 2.42 104 N/C.
Given data :
Gravitational force FG = 1.94 × 10-14 N
Downward electric feild E = 2.42 × 104 N/C
By using principle of Millikan oil drop model we can easily calculate charge on oil drop in terms of electron charge(e).
Step by step
Solved in 2 steps with 1 images
