mi/gallon. A simple random sample of 49 cars of this model is chosen and found to have a mean gas mileage of 27.5 mi/gallon. Construct a 97% confidence interval for the mean gas mileage for this car model.
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It is given that
Sample mean = 27.5
Population standard deviation = 4
Sample size = 49
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- The amount of time it takes students to travel to school can vary greatly depending on how far a student lives from the school and what mode of transportation they take to school. A student claims that the average travel time to school for his large district is 20 minutes. To further investigate this claim, he selects a random sample of 50 students from the school and finds that their mean travel time is 22.4 minutes with a standard deviation of 5.9 minutes. He would like to conduct a significance test to determine if there is convincing evidence that the true mean travel time for all students who attend this school is greater than 20 minutes. What are the appropriate hypotheses? A) H0: μ = 20 versus Ha: μ < 20, where μ = the true mean travel time for all students who attend this school B) H0: μ = 20 versus Ha: μ > 20, where μ = the true mean travel time for all students who attend this school C) H0: μ = 20 versus Ha: μ < 20, where μ = the mean travel time for the 50…A car company claims that its new SUV gets better gas mileage than its competitor's SUV. A random sample of 41 of its SUVS has a mean gas mileage of 15.2 miles per gallon (mpg). The population standard deviation is known to be 1.4 mpg. A random sample of 49 competitor's SUVs has a mean gas mileage of 14.8 mpg. The population standard deviation for the competitor is known to be 0.9 mpg. Test the company's claim at the 0.02 level of significance. Let the car company's SUVs be Population 1 and let the competitor's SUVs be Population 2. Step 2 of 3: Compute the value of the test statistic. Round your answer to two decimal places.A group of students sampled water from 34 lakes in St. Joseph County. If the mean dissolvedoxygen level was 3.2 with a standard deviation of .57 find a 90% confidence interval for thedissolved oxygen levels in St Joseph County lakes.
- A random sample of 250 students at a university finds that these students take a mean of 15 credit hours per quarter with a standard deviation of 2.5 credit hours. The 99% confidence interval for the mean is 15+-0.407. Interpret the interval.An SRS of 27 students at NYU gave an average height of 5.4 feet and a standard deviation of .1 feet. Find a 90% confidence interval for the mean height of students at NYU.The water consumption per week by Brampton residences is normally distributed with an average of 125 gallons of water and a standard deviation of 10 gallons. The city of Brampton claims that the average water consumed in the state of Brampton is not 125 gallons. A team of AU students draws a simple random sample of 10 residences and find the mean consumption value of 120.3 gallons. Calculate the Zc and p-value showing all the steps.
- The gas mileage for a certain model of car is known to have a standard deviation of 6 mi/gallon. A simple random sample of 36 cars of this model is chosen and found to have a mean gas mileage of 28.4 mi/gallon. Construct a 99% confidence interval for the mean gas mileage for this car model.A study is conducted to find the mean life of a certain manufacturer's car batteries. A random sample of 34 batteries is selected and a mean of 47.5 months with a standard deviation of 7.3 months is found. Find a 95% confidence interval for the mean battery life.A study has been made to compare the nicotine contents of two brands of cigarettes. Ten cigarettes of Brand A had an average nicotine content of 4.3 milligrams with a standard deviation of 0.6 milligram. Eight cigarettes of Brand B had an average nicotine content of 3 milligrams with a standard deviation of 0.4 milligram. Assume that the two sets of data are independent random samples from normal populations with equal variances. Answer the following, and round off your answer to three decimal places. (a) Find a pooled estimate of the population standard deviation. (b) Construct a 95% confidence interval for the difference between the mean nicotine contents of the two brands of cigarettes. (☐☐)
- Bone mineral density (BMD) is a measure of bone strength. Studies show that BMD declines after age 45. The impact of exercise may increase BMD. A random sample of 59 women between the ages of 41 and 45 with no major health problems were studied. The women were classified into one of two groups based upon their level of exercise activity: walking women and sedentary women. The 39 women who walked regularly had a mean BMD of 5.96 with a standard deviation of 1.22. The 20 women who are sedentary had a mean BMD of 4.41 with a standard deviation of 1.02. Which of the following inference procedures could be used to estimate the difference in the mean BMD for these two types of womenA car company claims that its new SUV gets better gas mileage than its competitor's SUV. A random sample of 35 of its SUVs has a mean gas mileage of 16.7 miles per gallon (mpg). The population standard deviation is known to be 0.9 mpg. A random sample of 42 competitor's SUVS has a mean gas mileage of 16.4 mpg. The population standard deviation for the competitor is known to be 0.6 mpg. Test the company's claim at the 0.02 level of significance. Let the car company's SUVs be Population 1 and let the competitor's SUVS be Population 2. Step 1 of 3: State the null and alternative hypotheses for the test. Fill in the blank below. Họ :-1 = M2 Ha М2A car company claims that its new SUV gets better gas mileage than its competitor's SUV. A random sample of 49 of its SUVs has a mean gas mileage of 17.1 miles per gallon (mpg). The population standard deviation is known to be 1.3 mpg. A random sample of 33 competitor's SUVS has a mean gas mileage of 16.3 mpg. The population standard deviation for the competitor is known to be 1.6 mpg. Test the company's claim at the 0.05 level of significance. Let the car company be Population 1 and let the competitor be Population 2. Step 2 of 3: Compute the value of the test statistic. Round your answer to two decimal places.
