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Microbiologists use acid-alcohol when performing a cell stain of the pathogen Mycobacterium tuberculosis. A common recipe is to make 3%weven HCl in ethanol. HCI has a formula weight of 36.46 grams per mole. If the stock solution of HCI is 2 moles per 1000 mL, how many mL of HCl need to be added to achieve a final volume of 25 mL of acid alcohol solution? Report your answer to two decimal places. Algebra can be used to solve this problem! In this context, the percentages act as concentrations. Therefore, it is possible to use m,v, = m,v2 and use the percentages as the concentration values. We can solve for m, by converting the molarity of HCl into a percentage using its formula weight. m, Mol HCI X 1000 mL 36.46 g HCI m1 = х 100 %3D %HСІ mol HCI Then substitute this value of m, into the equation mįv1 = m2v2 and solve for v, m2V2 (3%) (v2) V, = m1 ( 36.46 g HCI mị Mol HCI 1 mol HCI (100) 1000 mL Solve for v, in a single step using Excel to avoid causing rounding error!

Microbiologists use acid-alcohol when performing a cell stain of the pathogen Mycobacterium tuberculosis. A common recipe is to make 3%weven HCl in ethanol. HCI has a formula weight of 36.46 grams per mole. If the stock solution of HCI is 2 moles per 1000 mL, how many mL of HCl need to be added to achieve a final volume of 25 mL of acid alcohol solution? Report your answer to two decimal places. Algebra can be used to solve this problem! In this context, the percentages act as concentrations. Therefore, it is possible to use m,v, = m,v2 and use the percentages as the concentration values. We can solve for m, by converting the molarity of HCl into a percentage using its formula weight. m, Mol HCI X 1000 mL 36.46 g HCI m1 = х 100 %3D %HСІ mol HCI Then substitute this value of m, into the equation mįv1 = m2v2 and solve for v, m2V2 (3%) (v2) V, = m1 ( 36.46 g HCI mị Mol HCI 1 mol HCI (100) 1000 mL Solve for v, in a single step using Excel to avoid causing rounding error!

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Microbiologists use acid-alcohol when performing a cell stain of the pathogen Mycobacterium tuberculosis. A common recipe is to make 3%weven HCl in ethanol. HCI has a formula weight of 36.46 grams per mole. If the stock solution of HCI is 2 moles per 1000 mL, how many mL of HCl need to be added to achieve a final volume of 25 mL of acid alcohol solution? Report your answer to two decimal places. Algebra can be used to solve this problem! In this context, the percentages act as concentrations. Therefore, it is possible to use m,v, = m,v2 and use the percentages as the concentration values. We can solve for m, by converting the molarity of HCl into a percentage using its formula weight. m, Mol HCI X 1000 mL 36.46 g HCI m1 = х 100 %3D %HСІ mol HCI Then substitute this value of m, into the equation mįv1 = m2v2 and solve for v, m2V2 (3%) (v2) V, = m1 ( 36.46 g HCI mị Mol HCI 1 mol HCI (100) 1000 mL Solve for v, in a single step using Excel to avoid causing rounding error!
Transcribed Image Text:Microbiologists use acid-alcohol when performing a cell stain of the pathogen Mycobacterium tuberculosis. A common recipe is to make 3%weven HCl in ethanol. HCI has a formula weight of 36.46 grams per mole. If the stock solution of HCI is 2 moles per 1000 mL, how many mL of HCl need to be added to achieve a final volume of 25 mL of acid alcohol solution? Report your answer to two decimal places. Algebra can be used to solve this problem! In this context, the percentages act as concentrations. Therefore, it is possible to use m,v, = m,v2 and use the percentages as the concentration values. We can solve for m, by converting the molarity of HCl into a percentage using its formula weight. m, Mol HCI X 1000 mL 36.46 g HCI m1 = х 100 %3D %HСІ mol HCI Then substitute this value of m, into the equation mįv1 = m2v2 and solve for v, m2V2 (3%) (v2) V, = m1 ( 36.46 g HCI mị Mol HCI 1 mol HCI (100) 1000 mL Solve for v, in a single step using Excel to avoid causing rounding error!
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