-mg=Dapparent weight of object m= opparent mass at object = 100g 9= 993.18 drn Vニtrh %3D 9= 978 dyu S- density of abject = 5.51 9 Cm 3 P= density of water= 1-1 VE valume of object=18.14 cm w= (P-P)JU Find differen tiad emar of g sh=or= 0.0s cm %3D sm'=0.5g
-mg=Dapparent weight of object m= opparent mass at object = 100g 9= 993.18 drn Vニtrh %3D 9= 978 dyu S- density of abject = 5.51 9 Cm 3 P= density of water= 1-1 VE valume of object=18.14 cm w= (P-P)JU Find differen tiad emar of g sh=or= 0.0s cm %3D sm'=0.5g
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![W=mg%=
m= apparent mass at abject = 100g
apparent weight af object
93D993,18 dra
Vニtrh
9=978 dyu
Pé density of abject = 5.51
Cn 3
2=density of water= 1-9
Vs valume of object =18.14 cm
3.
%3D
Cu3
wE(B-)さび
Find differen tial
erar of
sh=or%3DD.0s cm
om'=0.5g
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbf87e182-55d2-4d48-9c03-0d2f107a76b8%2Fe7935467-c00b-4b64-87c0-8dcc7ada937f%2F4cxy7ze_processed.jpeg&w=3840&q=75)
Transcribed Image Text:W=mg%=
m= apparent mass at abject = 100g
apparent weight af object
93D993,18 dra
Vニtrh
9=978 dyu
Pé density of abject = 5.51
Cn 3
2=density of water= 1-9
Vs valume of object =18.14 cm
3.
%3D
Cu3
wE(B-)さび
Find differen tial
erar of
sh=or%3DD.0s cm
om'=0.5g
%3D
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