### Chemical Reaction Problem**Reaction Equation:**\[ \text{Mg}^{2+} + \text{Cl}_2 + 2\text{NaHCO}_3 \rightarrow \text{MgCO}_3 + 2\text{NaCl} + \text{H}_2\text{O} + \text{CO}_2 \]**Question:**If the reaction produces 0.005g of MgCO₃, then about how many grams of Mg were in the water? (Show your work)### Solution Steps:1. **Determine the molar mass of MgCO₃:** - Magnesium (Mg): 24.305 g/mol - Carbon (C): 12.011 g/mol - Oxygen (O): 3 × 16.00 g/mol = 48.00 g/mol - Total molar mass of MgCO₃: 24.305 + 12.011 + 48.00 = 84.316 g/mol2. **Calculate the moles of MgCO₃ produced:** - Given mass of MgCO₃ = 0.005 g - Moles of MgCO₃ = (mass of MgCO₃) / (molar mass of MgCO₃) - Moles of MgCO₃ = 0.005 g / 84.316 g/mol ≈ 5.93 × 10⁻⁵ mol3. **Determine the moles of Mg:** - From the balanced chemical equation, 1 mole of MgCO₃ is produced from 1 mole of Mg. - Therefore, moles of Mg = moles of MgCO₃ = 5.93 × 10⁻⁵ mol4. **Calculate the mass of Mg:** - Molar mass of Mg = 24.305 g/mol - Mass of Mg = (moles of Mg) × (molar mass of Mg) - Mass of Mg = 5.93 × 10⁻⁵ mol × 24.305 g/mol ≈ 1.44 × 10⁻³ g**Answer:**Approximately 0.00144 grams of Mg was in the water.

Given : Mass of MgCO3 produced = 0.005 g Also, Molar mass of MgCO3 = 84 g/mol Molar mass of Mg =…

Answered: Mg²+ + Cl₂ + 2NaHCO3 → MgCO3 + 2NaCl +…

Mg²+ + Cl₂ + 2NaHCO3 → MgCO3 + 2NaCl + H₂O + CO₂ If the reaction makes 0.005g of MgCO3 then about how many grams of Mg was in the water? (Show your work)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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