M₁=•fc'•b•d² w. (1-0.59 w) 200-106 = 0.9.20.7-300-480² w-(1-0.59 w)

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Q: M₁=•fc'·b·d² w. (1-0.59 w) 200-106 = 0.9.20.7-300-480² w-(1-0.59 w)

A: Sol:- 200⋅106=0.9⋅20.7⋅300⋅4802⋅w(1-0.59w) It an be re-written as :-Let…

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Q: M₂=•fc'•b•d² w. (1-0.59 w) 200-10% =0.9.20.7-300-480² w (1-0.59 w)

A: Sol:- Letf(w)=0.9⋅20.7⋅300⋅4802⋅w(1-0.59w)-200⋅106Using Fixed Point Iteration methodHere…

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Q: M₁=0.0.85.fe'.a.b.d- -(480-2) 200-106 = 0.9.0.85-20.7. a 300-480-

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Q: M₁=0.0.85.fc'.a.b. d-- 5.fc²·a·b (d-a) 2 0-(480-) 2 200.106 = 0.9.0.85-20.7.a.300 480-

A: Sol:- Let f(a)=0.9⋅0.85⋅20.7⋅a⋅300(480-a2)-200⋅106Here f(97)=-1159168.925<0 and…

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