Methyl salicylate (oil of wintergreen) is prepared by heating salicylic acid,C7 H6O3, with methanol,CH3OH,C7H6 O3 + CH3 OH → C3Hs O3 + H2OIn an experiment, 1.30 g of salicylic acid is reacted with 11.9 g of methanol. The yield of methyl salicylate, Cg Hs O3, is 1.13 g. What is the percentage yield?Percentage yield =%

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Methyl salicylate (oil of wintergreen) is prepared by heating salicylic acid, C7 H6 O3, with methanol, CH3OH, C7H6 O3 + CH3 OH → C3Hs O3 + H20 In an experiment, 1.30 g of salicylic acid is reacted with 11.9 g of methanol. The yield of methyl salicylate, Cs Hs O3, is 1.13 g. What is the percentage yield? Percentage yield = %

Methyl salicylate (oil of wintergreen) is prepared by heating salicylic acid, C7 H6 O3, with methanol, CH3OH, C7H6 O3 + CH3 OH → C3Hs O3 + H20 In an experiment, 1.30 g of salicylic acid is reacted with 11.9 g of methanol. The yield of methyl salicylate, Cs Hs O3, is 1.13 g. What is the percentage yield? Percentage yield = %

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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