Methanol undergoes combustion according to the equation2 CH3OH (1) + 3 02 (e) → 2 CO2 (e) + 4 H2O)Find the amount of heat given off from the combustion of 64 g CH3OH.AH = -1452.8 kJ-1452.8 kJO -726.4 kJO -2179.2 kJ-2905.6 kJ

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Methanol undergoes combustion according to the equation 2 CH3OH (1) + 3 O2 (4) → 2 CO2 (e) + 4 H20µ) Find the amount of heat given off from the combustion of 64 g CH3OH. AH = -1452.8 kJ O -1452.8 kJ O -726.4 kJ O -2179.2 kJ -2905.6 kJ

Methanol undergoes combustion according to the equation 2 CH3OH (1) + 3 O2 (4) → 2 CO2 (e) + 4 H20µ) Find the amount of heat given off from the combustion of 64 g CH3OH. AH = -1452.8 kJ O -1452.8 kJ O -726.4 kJ O -2179.2 kJ -2905.6 kJ

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Methanol undergoes combustion according to the equation
2 CH3OH (1) + 3 02 (e) → 2 CO2 (e) + 4 H2O)
Find the amount of heat given off from the combustion of 64 g CH3OH.
AH = -1452.8 kJ
-1452.8 kJ
O -726.4 kJ
O -2179.2 kJ
-2905.6 kJ

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