Methanol (SG=0.792) is contained in a large tank under a pressure of 350000 Pa absolute. When a valve on the bottom of the tank is opened, the methanol drains freely though a 0.02 m ID tube whose outlet is 7.00 m below the surface of the methanol. The pressure at the outlet of the discharge pipe is 101325 Pa. Some useful constants and conversions: g = 9.8 m/s2 , Pref = 1000 kg/m3 . a. Draw the system. Label points I and 2 (where you will define A= 2-1) and label the variables with values b Write the general form of the energy
Methanol (SG=0.792) is contained in a large tank under a pressure of 350000 Pa absolute. When a valve on the bottom of the tank is opened, the methanol drains freely though a 0.02 m ID tube whose outlet is 7.00 m below the surface of the methanol. The pressure at the outlet of the discharge pipe is 101325 Pa. Some useful constants and conversions: g = 9.8 m/s2 , Pref = 1000 kg/m3 .
a. Draw the system. Label points I and 2 (where you will define A= 2-1) and label the
variables with values
b Write the general form of the energy balance. Cancel out negligible terms, and state the
keyword/assumption to justify. Simplify to the resultant energy balance.
c.) Assume the diameter of the tank is very big compared to the drain tube velocity, which make
the velocity of liquid in the tank equal to zero. Estimate the methanol discharge velocity in
the drain tube in m/s.
*hint: divide your EB by m to eliminate m and V. Recall, n = pV = pvA and = v/m=1/p
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images