Mesh – current analysis produces the following two equations: (5 – j4) I – (-j4)l, = 10040° (4 + j3 – j4)l2 – (-j4)I, = 0 Using Cramer's rule to solve the equations for the loop current I, and I I= 400-100j I= -400j True O False

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Mesh – current analysis produces the following two equations:
(5 – j4) I – (-j4)I, = 10040°
(4 + j3 – j4)l, – (-j4)l = 0
%3D
Using Cramer's rule to solve the equations for the loop current I, and I,
I;= 400-100j
I= -400j
O True
False
Transcribed Image Text:Mesh – current analysis produces the following two equations: (5 – j4) I – (-j4)I, = 10040° (4 + j3 – j4)l, – (-j4)l = 0 %3D Using Cramer's rule to solve the equations for the loop current I, and I, I;= 400-100j I= -400j O True False
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