Menthol, from oil of mint, has a characteristic odor. The compound contains only C, H, and O. If 89.6 mg of menthol burns completely in O2, and gives 252 mg of CO2 and 103 mg of H₂O, what is the empirical formula of menthol? (Enter the elements in the order: C, H, O.) Empirical formula:

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### Determining the Empirical Formula of Menthol

**Problem Statement:**

Menthol, derived from mint oil, is known for its characteristic odor. This compound is composed solely of Carbon (C), Hydrogen (H), and Oxygen (O). When 89.6 mg of menthol is completely combusted in Oxygen (O₂), it produces 252 mg of Carbon Dioxide (CO₂) and 103 mg of Water (H₂O). You are required to determine the empirical formula of menthol.

**Question:**

Given the data above, what is the empirical formula of menthol?
(Enter the elements in the order: C, H, O.)

**Solution Box:**

Empirical formula: [______]

**Steps to Solve:**

1. **Determine the moles of Carbon in CO₂:**
   - Each mole of CO₂ contains 1 mole of C.
   - Calculate the moles of CO₂: \\[\frac{252 \text{ mg}}{44 \text{ mg/mmol}} = 5.7273 \text{ mmol CO₂}\\]
   - Therefore, moles of C: \\[5.7273 \text{ mmol C}\\]

2. **Determine the moles of Hydrogen in H₂O:**
   - Each mole of H₂O contains 2 moles of H.
   - Calculate the moles of H₂O: \\[\frac{103 \text{ mg}}{18 \text{ mg/mmol}} = 5.7222 \text{ mmol H₂O}\\]
   - Therefore, moles of H: \\[5.7222 \times 2 = 11.4444 \text{ mmol H}\\]

3. **Determine the mass of Carbon and Hydrogen:**
   - Mass of C: \\[5.7273 \text{ mmol} \times 12 \text{ mg/mmol} = 68.7276 \text{ mg C}\\]
   - Mass of H: \\[11.4444 \text{ mmol} \times 1 \text{ mg/mmol} =11.4444 \text{ mg H}\\]

4. **Determine the mass of Oxygen in menthol:**
   - Total mass of menthol: 89.6 mg
   - Mass of O: \\[89.6 \text{ mg} - (68.7276 \text
Transcribed Image Text:### Determining the Empirical Formula of Menthol **Problem Statement:** Menthol, derived from mint oil, is known for its characteristic odor. This compound is composed solely of Carbon (C), Hydrogen (H), and Oxygen (O). When 89.6 mg of menthol is completely combusted in Oxygen (O₂), it produces 252 mg of Carbon Dioxide (CO₂) and 103 mg of Water (H₂O). You are required to determine the empirical formula of menthol. **Question:** Given the data above, what is the empirical formula of menthol? (Enter the elements in the order: C, H, O.) **Solution Box:** Empirical formula: [______] **Steps to Solve:** 1. **Determine the moles of Carbon in CO₂:** - Each mole of CO₂ contains 1 mole of C. - Calculate the moles of CO₂: \\[\frac{252 \text{ mg}}{44 \text{ mg/mmol}} = 5.7273 \text{ mmol CO₂}\\] - Therefore, moles of C: \\[5.7273 \text{ mmol C}\\] 2. **Determine the moles of Hydrogen in H₂O:** - Each mole of H₂O contains 2 moles of H. - Calculate the moles of H₂O: \\[\frac{103 \text{ mg}}{18 \text{ mg/mmol}} = 5.7222 \text{ mmol H₂O}\\] - Therefore, moles of H: \\[5.7222 \times 2 = 11.4444 \text{ mmol H}\\] 3. **Determine the mass of Carbon and Hydrogen:** - Mass of C: \\[5.7273 \text{ mmol} \times 12 \text{ mg/mmol} = 68.7276 \text{ mg C}\\] - Mass of H: \\[11.4444 \text{ mmol} \times 1 \text{ mg/mmol} =11.4444 \text{ mg H}\\] 4. **Determine the mass of Oxygen in menthol:** - Total mass of menthol: 89.6 mg - Mass of O: \\[89.6 \text{ mg} - (68.7276 \text
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