Medicare Hospital Insurance The average yearly Medicare Hospital Insurance benefit per person was $4064 in a recent year.Suppose the benefits are normally distributed with a standard deviation of $460. Round the final answers to at least four decimalplaces and intermediate z-value calculations to two decimal places.Part 1 of 2Find the probability that the mean benefit for a random sample of 29 patients is less than $3910.P(X<3910) =Part 2 of 2Find the probability that the mean benefit for a random sample of 29 patients is more than $4140.P(X> 4140)

Answered: Medicare Hospital Insurance The average…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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When Freshman 15 The term "Freshman 15" refers to the claim that college students typically gain 15 lb during their freshman year at college. Assume that the amounts of weight that male college students gain during their freshman year are normally distributed with a mean of 2.6 lb and a standard deviation of 10.8 1b (based on Data Set 13 "Freshman 15"). Find the probability that a randomly selected male college student gains 15 lb or more during his freshman year. What does the result suggest about the claim of the "Freshman 15"?
In Math 150 class the points of the final exam are normally distributedWith a mean of 72 and standard deviation of 10. The top 15% will receive an A gradeFind the lowest score in the final exam that would qualify a student for an A grade.
IQ scores are normally distributed with a mean of 100 and a variance of 225. What percentage of people score between 130 and 145?
An Intelligence test score for adults is normally distributed with a mean of 100 and population standard deviation of 15. What is the probability we could select a sample of 64 adults and find that the mean of this sample is between 98 and 103? (answer rounded to 2d.ps)
In the country of United States of Heightlandia, the height measurements of ten-year-old children are approximately normally distributed with a mean of 53.3 inches, and standard deviation of 2.2 inches.What is the probability that the height of a randomly chosen child is between 51.3 and 57.1 inches? Do not round until you get your your final answer, and then round to 3 decimal places.Answer=___________ (Round your answer to 3 decimal places.)
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A mathematics professor one to determine whether there is a different in the final average just between the past two semester (semester 1 and semester 2) of his business is statistics classes. For a random sample of 16 students from semester 1, the mean of the final averages was 75 with a standard deviation of 4. For a random sample of 9 students from semester 2, the mean was 73 with a standard deviation of 6. Choose the correct answer
Suppose the mean income of firms in the industry for a year is 80 million dollars with a standard deviation of 55 million dollars. If incomes for the industry are distributed normally, what is the probability that a randomly selected firm will earn more than 88 million dollars? Round your answer to four decimal places.
College students average 8.2 hours of sleep per night with a standard deviation of 45 minutes. If the amount of sleep is normally distributed, what proportion of college students sleep for more than 9 hours? Probability = %3D
The distribution of scores for an exam follow the rule of thumb for standard deviation. If the average score on the exam is 75 and the standard deviation is 5, what percentage of students would you expect to score between 65 and 85 on the exam (to 2 significant digits)?
College students average 7.1 hours of sleep per night with a standard deviation of 35 minutes. If the amount of sleep is normally distributed, what proportion of college students sleep for more than 8.1 hours? Probability =
* Your answer is incorrect. Service time for a customer coming through a checkout counter in a retail store is a random variable with the mean of 3.5 minutes and standard deviation of 3.5 minutes. Suppose that the distribution of service time is fairly close to a normal distribution. Suppose there are two counters in a store, n₁ = 2 customers in the first line and n₂ = 13 customers in the second line. Find the probability that the difference between the mean service time for the shorter line X₁ and the mean service time for the longer one X₂ is more than 0.1 minutes. Assume that the service times for each customer can be regarded as independent random variables. Round your answer to two decimal places (e.g. 98.76). P = i 98.80

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