**Problem 4-174: Beam Loading Analysis** **Objective:** Replace the distributed loading on the beam with an equivalent resultant force and specify its location from point A. **Description:** The beam shown is subject to a non-uniform distributed load described by the equation: \[ w = (x^2 + 3x + 100) \, \text{lb/ft} \] The load starts at 100 lb/ft at point A and increases to 370 lb/ft at point B, across a span of 15 feet. The load is applied vertically downward along the length of the beam. **Diagram Explanation:** - **Vertical Axis (w):** Represents the intensity of distributed load in pounds per foot (lb/ft). - **Horizontal Axis (x):** Represents the length of the beam from point A to point B, which is 15 feet. - **Graph:** Exhibits the increasing load distribution from 100 lb/ft at point A to 370 lb/ft at point B, in an upward parabolic manner consistent with the given load equation. To solve the problem, calculate the equivalent resultant force of the distributed load and determine its point of action on the beam measured from point A. This involves integrating the load distribution equation over the length of the beam to find the total load and its centroid.
**Problem 4-174: Beam Loading Analysis** **Objective:** Replace the distributed loading on the beam with an equivalent resultant force and specify its location from point A. **Description:** The beam shown is subject to a non-uniform distributed load described by the equation: \[ w = (x^2 + 3x + 100) \, \text{lb/ft} \] The load starts at 100 lb/ft at point A and increases to 370 lb/ft at point B, across a span of 15 feet. The load is applied vertically downward along the length of the beam. **Diagram Explanation:** - **Vertical Axis (w):** Represents the intensity of distributed load in pounds per foot (lb/ft). - **Horizontal Axis (x):** Represents the length of the beam from point A to point B, which is 15 feet. - **Graph:** Exhibits the increasing load distribution from 100 lb/ft at point A to 370 lb/ft at point B, in an upward parabolic manner consistent with the given load equation. To solve the problem, calculate the equivalent resultant force of the distributed load and determine its point of action on the beam measured from point A. This involves integrating the load distribution equation over the length of the beam to find the total load and its centroid.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
change the disturbed load formula to w= (0.08x^3 + 100) lb/ft
*you must use integration for this
![**Problem 4-174: Beam Loading Analysis**
**Objective:**
Replace the distributed loading on the beam with an equivalent resultant force and specify its location from point A.
**Description:**
The beam shown is subject to a non-uniform distributed load described by the equation:
\[ w = (x^2 + 3x + 100) \, \text{lb/ft} \]
The load starts at 100 lb/ft at point A and increases to 370 lb/ft at point B, across a span of 15 feet. The load is applied vertically downward along the length of the beam.
**Diagram Explanation:**
- **Vertical Axis (w):** Represents the intensity of distributed load in pounds per foot (lb/ft).
- **Horizontal Axis (x):** Represents the length of the beam from point A to point B, which is 15 feet.
- **Graph:** Exhibits the increasing load distribution from 100 lb/ft at point A to 370 lb/ft at point B, in an upward parabolic manner consistent with the given load equation.
To solve the problem, calculate the equivalent resultant force of the distributed load and determine its point of action on the beam measured from point A. This involves integrating the load distribution equation over the length of the beam to find the total load and its centroid.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe38bb56b-da42-44ea-a3d9-c87319b95f18%2F5e4af096-3736-426f-ba7e-98969b10caa2%2F8icjpak_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem 4-174: Beam Loading Analysis**
**Objective:**
Replace the distributed loading on the beam with an equivalent resultant force and specify its location from point A.
**Description:**
The beam shown is subject to a non-uniform distributed load described by the equation:
\[ w = (x^2 + 3x + 100) \, \text{lb/ft} \]
The load starts at 100 lb/ft at point A and increases to 370 lb/ft at point B, across a span of 15 feet. The load is applied vertically downward along the length of the beam.
**Diagram Explanation:**
- **Vertical Axis (w):** Represents the intensity of distributed load in pounds per foot (lb/ft).
- **Horizontal Axis (x):** Represents the length of the beam from point A to point B, which is 15 feet.
- **Graph:** Exhibits the increasing load distribution from 100 lb/ft at point A to 370 lb/ft at point B, in an upward parabolic manner consistent with the given load equation.
To solve the problem, calculate the equivalent resultant force of the distributed load and determine its point of action on the beam measured from point A. This involves integrating the load distribution equation over the length of the beam to find the total load and its centroid.
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