The uniform 1,157-mm link AB slides up on frictionless rollers as shown below. At the instant shown, the link AB is vertical and the absolute velocity of point A is 19.9 m/s in the direction shown. Ignore the link thickness and roller diametres. For this configuration, 01=39 degrees and O2=25 degrees as shown. VA 01 A G Calculate the absolute velocity of the centre of mass at G. Give your answer in the form Z = 2 VGx + VGy in m/s where vGx is the horizontal component of the velocity vector (positive to the right) and VGy is the vertical component of the velocity vector (positive upwards). Round your final answer to two decimal places.
The uniform 1,157-mm link AB slides up on frictionless rollers as shown below. At the instant shown, the link AB is vertical and the absolute velocity of point A is 19.9 m/s in the direction shown. Ignore the link thickness and roller diametres. For this configuration, 01=39 degrees and O2=25 degrees as shown. VA 01 A G Calculate the absolute velocity of the centre of mass at G. Give your answer in the form Z = 2 VGx + VGy in m/s where vGx is the horizontal component of the velocity vector (positive to the right) and VGy is the vertical component of the velocity vector (positive upwards). Round your final answer to two decimal places.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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
Transcribed Image Text:The uniform 1,157-mm link AB slides up on
frictionless rollers as shown below. At the
instant shown, the link AB is vertical and the
absolute velocity of point A is 19.9 m/s in the
direction shown. Ignore the link thickness and
roller diametres. For this configuration, 01=39
degrees and O2=25 degrees as shown.
VA
01
A
G
Calculate the absolute velocity of the centre
of mass at G. Give your answer in the form Z =
2 VGx + VGy in m/s where vGx is the horizontal
component of the velocity vector (positive to
the right) and VGy is the vertical component of
the velocity vector (positive upwards). Round
your final answer to two decimal places.
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