Measurements of the Ticker Tape (for only 1 rubber band) F Units 1st strip (cm) 2nd strip (cm) 3rd strip(cm) 4th strip(cm) 5th strip (cm) F=1 0.55 1.1 1.6 2.2 2.75 The length of strip in each chart represents the total distance travelled by the cart over a time interval of 0.10 seconds. Recall that the total distance travelled over a unit time gives the average velocity of the moving body, or speed when travelling in straight line. Hence, each strip represents the average velocity of the cart over a time interval of 0.10 seconds. Please Answer: (F= 1 only) Compute for the average velocity of the cart over each time interval by measuring the length of the strip and dividing it by the time covered to travel such distance. Example, if the length of the strip is equal to 2.5 cm, then the average velocity during that time interval will be Vave = 2.5 cm / 0.10sec = 25 cm/s 2. Next, determine the difference in the average velocities (Δv) of the cart between two successive time intervals. Example, you can get the difference in the average velocities between strips 1 & 2, between strips 2 & 3, and so on. 3. Compute for the average acceleration.
Force and Accelaration
A group of students conducted an experiment to determine the relationship between the force acting on the object and its acceleration. They used identical rubber bands to pull the cart as shown in Figure 8. They varied the number of rubber bands to vary the force acting on the cart. They started with 1 rubber band, then with 2, 3, and 4 rubber bands, making sure that they stretched the rubber bands to the same length every time they pull the cart. They used a ticker tape timer to determine the acceleration of the cart. A ticker tape was connected to the cart such that when the cart was pulled, the paper tape will be pulled through the timer. And as the paper tape was pulled through the timer, small dots are formed on the tape.
Starting with the tape for 1 rubber band, they marked the first clear dot and every 6th dot thereafter and cut the tape along these points (Figure 9). Then they pasted the strips side by side in order on a graphing paper to produce the tape chart for F=1 unit.
.Measurements of the Ticker Tape (for only 1 rubber band)
|
F Units |
1st strip (cm) |
2nd strip (cm) |
3rd strip(cm) |
4th strip(cm) |
5th strip (cm)
|
|
F=1 |
0.55 |
1.1 |
1.6 |
2.2 |
2.75
|
The length of strip in each chart represents the total distance travelled by the cart over a time interval of 0.10 seconds. Recall that the total distance travelled over a unit time gives the average velocity of the moving body, or speed when travelling in straight line. Hence, each strip represents the average velocity of the cart over a time interval of 0.10 seconds.
Please Answer: (F= 1 only)
- Compute for the average velocity of the cart over each time interval by measuring the length of the strip and dividing it by the time covered to travel such distance. Example, if the length of the strip is equal to 2.5 cm, then the average velocity during that time interval will be
Vave = 2.5 cm / 0.10sec
= 25 cm/s
2. Next, determine the difference in the average velocities (Δv) of the cart between two successive time intervals.
Example, you can get the difference in the average velocities between strips 1 & 2, between strips 2 & 3, and so on.
3. Compute for the average acceleration.
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