**Problem 31 of 32: Organic Reaction Pathway**In this problem, a chemical reaction pathway is provided, showing the transformation of a given compound through a series of reactions. The pathway consists of two main steps, each involving specific reagents and conditions. Below is the detailed breakdown:### Initial CompoundThe structure at the top represents an alkene with a specific arrangement of carbon atoms and a double bond. The molecular framework can be interpreted as two adjacent six-carbon chains, which together form the structure known as an alkene.### Step 1- **Reagents:** mCPBA, CH₂Cl₂- **Description:** - mCPBA (meta-Chloroperoxybenzoic acid) is commonly used for epoxidation, which adds an oxygen atom across the double bond of an alkene, forming an epoxide. - CH₂Cl₂, or dichloromethane, serves as the solvent in this reaction.### Step 2- **Reagents:** 1. NaCN 2. H₂O- **Description:** - NaCN (Sodium cyanide) is a nucleophile that may react with the epoxide, opening the ring. - H₂O (water) could be used to finalize the structure post-reaction, possibly converting intermediates into the final alcohol or cyanohydrin product.### Diagram Explanation- **Diagram Layout:** - The flowchart layout presents the transformation steps using arrows to indicate progression from the initial compound to intermediates and final products. - The broken-line boxes labeled "Select to Draw" suggest interactive elements where users are expected to sketch molecular structures as part of the learning exercise.This setup is typical for studying reaction mechanisms, offering practice in predicting and understanding the outcomes of synthetic organic transformations.

m-CPBA ( meta chloro perbezoic acid) is a oxidizing reagent it reacts with alkene to form an epoxide ring and ring opening takes place in presence of nucleophile which is NaCN after work up with H2O gives desired product.m-CPBA reacts with alkene to form epoxide, which is a three-membered ring containing an oxygen atom.The reaction follow the following steps-The epoxide ring opening by NaCN and water is a base-catalyzed reaction that follows an SN2 mechanism. The nucleophile, which is the cyanide ion (CN-) from NaCN, attacks the less substituted or less hindered side of the epoxide ring , breaking the ring and forming the product with negative charge oxygen.The oxygen of the epoxide becomes negatively charged and then abstracts a proton from water, forming a hydroxyl group.The major product is shown below