McDonald's has one of the slowest drive-thru wait times for fast food restaurants. The drive-thru waiting times are normally distributed with a mean of 273 seconds and a standard deviation of 51 seconds. - Z(S) a. Find the probability that a randomly chosen customer will wait between 260 and 280 seconds. 260-280 - 20 2= 273 4.97 51 120 171 222 273 324 376 426 16 42.5 168- -95 977 Answer obtained by hand: - Seconds = Answer obtained from graphing calculator: 7.5
McDonald's has one of the slowest drive-thru wait times for fast food restaurants. The drive-thru waiting times are normally distributed with a mean of 273 seconds and a standard deviation of 51 seconds. - Z(S) a. Find the probability that a randomly chosen customer will wait between 260 and 280 seconds. 260-280 - 20 2= 273 4.97 51 120 171 222 273 324 376 426 16 42.5 168- -95 977 Answer obtained by hand: - Seconds = Answer obtained from graphing calculator: 7.5
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
How was 7.5 obtained?
![273
51
McDonald's has one of the slowest drive-thru wait times for fast food restaurants.
The drive-thru waiting times are normally distributed with a mean of 273 seconds
and a standard deviation of 51 seconds.
+2(S)
a.
Find the probability that a randomly chosen customer will wait between 260 and 280 seconds.
260-280
2= 273 - 20
51
120 171 222 273 324 375 426
16 1-61-
-95
42.5
47.7
Answer obtained by hand:
-
Seconds
= 4.97
Answer obtained from graphing calculator:
7.5](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9e669517-7414-4493-8c49-a6f19c013069%2Feea7b914-1abb-4b76-9c4d-6bdc199eaecd%2F73thzp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:273
51
McDonald's has one of the slowest drive-thru wait times for fast food restaurants.
The drive-thru waiting times are normally distributed with a mean of 273 seconds
and a standard deviation of 51 seconds.
+2(S)
a.
Find the probability that a randomly chosen customer will wait between 260 and 280 seconds.
260-280
2= 273 - 20
51
120 171 222 273 324 375 426
16 1-61-
-95
42.5
47.7
Answer obtained by hand:
-
Seconds
= 4.97
Answer obtained from graphing calculator:
7.5
Expert Solution
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Step 1
Let X be the random variable from normal distribution with mean (μ) = 273 and standard deviation (σ) = 51
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