MC9: In wireless LAN communication, MACA is widely used. In this protocol, in order to avoid collision, a sender can send sender is granted the privilege to send a frame to the receiver only after it receives request signal to a receiver. The replied from the receiver. O RTS, RTS CTS, CTS RTS, CTS CTS RTS

MC9: In wireless LAN communication, MACA is widely used. In this protocol, in order to avoid collision, a sender can send sender is granted the privilege to send a frame to the receiver only after it receives request signal to a receiver. The replied from the receiver. O RTS, RTS CTS, CTS RTS, CTS CTS RTS

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter9: Computer Networks

Section: Chapter Questions

Problem 11VE

See similar textbooks

Similar questions

For NAT Network Address Translation Scenario: Jenny Bello is a small business owner selling and making customized computer peripherals. She has been finding it difficult to track her sales and inventories, however recently after an expert's advice, she adopted a Point of Sale (PoS) server. So, she can now track her sales and inventories at the store. However, she ran into another issue, the server can only be accessed within the store, because it has been assigned a private IPv4 address, it is not publicly accessible via the Internet. a) Why is not having the PoS server accessible over the Internet a problem for the business? b) What caused this problem? c) Propose a solution for the problem and explain how the solution works.
In wireless LAN communication, MACA is widely used. In this protocol, in order to avoid collision, a sender can send granted the privilege to send a frame to the receiver only after it receives replied from the receiver. -- request signal to a receiver. The sender is CTS, RTS RTS, RTS RTS, CTS O CTS, CTS
A deadlock occurs in the transport layer when the:a. checksum result is invalidb. transmission error is randomc. data transmission is bidirectionald.segment is lost
Q: In a structured overlay network, messages are routed according to the topology of the overlay. What is an important disadvantage of this approach?
It is necessary to investigate connectionless protocols as a potential substitute for connection-based protocols.
In a bit-oriented link-layer protocol, the start and end of a frame are each marked by a flag, which is a sequence of exactly 6 consecutive 1 bits. Bit stuffing is used during the rest of the frame: after sending 5 consecutive 1 bits, a 0 is added. The bits below contain an example frame, with the leftmost bit received first. The content of the frame is a sequence of bytes, sent most significant bit first. Put the values of the first four bytes of the frame content, in order, in the four answer boxes below. You may enter the values in either decimal (e.g. 76, 123) or hexadecimal (e.g. 2a, f7). 00101011111010001111110011100111110000111101111101010110100010010011111101101100100 57−240−123−229
Create a spanning tree for the given topology. Label all ports with their status i.e. Root, designated or block. Note: STP link costs are shown in brackets
It is necessary to do research on connectionless protocols in order to determine whether or not they can successfully replace connection-based protocols.
Computer networking subject rcs817
Task NW29. UDP is the simplest transport layer communication protocol. It contains a minimum amount of communication mechanisms. It is considered an unreliable protocol, and it is based on best-effort delivery services. UDP provides no acknowledgment mechanism, which means that the receiver does not send the acknowledgment for the received packet, and the sender also does not wait for the acknowledgment for the packet that it has sent. An end system sends 50 packets per second using the User Datagram Protocol (UDP) over a full duplex 100 Mbps Ethernet LAN connection. Each packet consists 1500B of Ethernet frame payload data. What is the throughput, when measured at the UDP layer? Task DS30
Answer true or false to the following questions and briefly justify your answer: With GBN, it is possible for the sender to receive an ACK for a packet that falls outside of its current window.
R6Fragmentation of an IP datagram takes place if its size is larger than the MTU of the subnet over which the datagram will be routed. Most IP datagram reassembly algorithms have a timer to avoid having a lost fragment tie up reassembly buffers forever. Suppose a datagram is fragmented into four fragments. The first three fragments arrive, but the last one is delayed. Eventually the timer goes off and the three fragments in the receiver's memory are discarded. A little later, the last fragment stumbles in. What should be done with it?