May I please get some help with 13C NMR for C6H10OI need help with tabulating chemical shifts, splitting, neighboring protons, integration, fragments.Are there any special features? **Title: Understanding the 13C NMR Spectrum of Unknown Compound #4****Introduction**This document presents the 13C Nuclear Magnetic Resonance (NMR) spectrum for a compound labeled as "Unknown #4". NMR spectroscopy is a powerful tool used to identify the structure of organic compounds by analyzing the magnetic properties of carbon atoms.**Graph Explanation**The graph displayed is a 13C NMR spectrum featuring several peaks along the x-axis, which represents the chemical shift in parts per million (ppm). The scale ranges from approximately 0 to 210 ppm. The y-axis represents the intensity of the signals, indicating the presence of different carbon environments within the compound.**Peak Analysis**- Significant peaks are observed at the following chemical shifts, suggesting specific carbon environments in the compound: - Near 14 ppm - Around 30 ppm - Close to 70 ppm - Approximately 125-140 ppm - About 180 ppm**Data Table**A table is included with specific numerical values, likely denoting chemical shifts, multiplicity, and coupling constants. The table might list the observed peaks or additional spectral data for analysis.- **SS:** 28, 3333- **SF:** 25, 975 (others: 125, 941)- **Other rows include various numerical entries likely used for internal referencing and detailed calculations.****Conclusion**This spectrum provides a basis for deducing the structure of Unknown Compound #4 through the interpretation of chemical shifts and the identification of carbon atom types, such as alkyl, alkene, or carbonyl carbons. Further analysis and comparison with known data can help in structurally elucidating and confirming the identity of the compound.

In 13C spectroscopy, the presence of non-equivalent carbon atoms and their count is determined. Besides, the types of carbon atoms a molecule adopts such as aromatic, the carbonyl is observed. The weak signals of 13C spectra of a molecule is due to the low abundance of 13C isotope, 1.0% of the sample has the magnetically active isotope and the low gyromagnetic ratio of the 13C nuclei. The molecular formula of the compound is C6H10O. The degree of unsaturation of the compound is two and the molecule contains two double bonds. The simplest nature of the provided spectra shows that the carbon atoms of the compounds are decoupled with the protons or the protons have not shown any role in splitting the signals of the 13C peaks. The spectra of the compound have a peak of less than 200 ppm. So the compound can have an aldehyde or ketone. But the peak at ∂=195 ppm shows the presence of an aldehyde group in the compound. Besides, the two peaks at 130-160 ppm show the double-bonded carbon. The presence of three peaks in the alkyl region at ∂ = 10-30 ppm shows the presence of alkyl groups. So, the expected structure of the compound is cis-3-hexenal. So, C5 resonates at 21 ppm, C6 resonates at 12 ppm. and C3 gives a peak at 35 ppm. Hence, the 13C spectra of the unknown compound are analyzed and found to be cis-3-hexenal.