Maximize Z= 150x1+125x2+95x3Subject toAssemblyInspection 1.5x1 +1x2 +0.5x3 <=30PackagingAnd x1, x2, x3 >=0h3.5x1 +2.75x2 +1.25x3 <= 1501x1 +0.75x2 +0.25x3 <= 10Break-even analysis

Given Data: Maximize z=150 x1+125x2+95x3 Assembly - 3.5x1+2.75x2+ 1.25x3<=x1150 Inspection -…

Answered: Maximize Z-150x1+125x2+95x3 Subject to…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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The following is a L.P.P: Max Z- 5X1+7X2+ 6X3 (Hundreds of dollars $) s.t: 3X1+ 4X2 + 2X3 -0 (production capacity; hours) (warehouse capacity: hundreds of sq. ft.) (demand for 6 oz. glasses: hundreds of cases) The optimal solution to the model as follows: Basis Св 5X1 7X2 S1 6X3 0.5 -1 S2 S3 RHS X2 S1 X1 1. -0.5 10 1. -3 10 1. -1 10 7. 1.6 -1.5 5n 8.5 120 C-Z 01 -2.5 -2 What effect on the optimal solution (value of Z) ,if we change b2 from 48.2 to 57.1 ?
Find the smallest postive integer solution to x^2 -29 y^2=1
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Q1) A retail. Store stocks two types of shirts A and B. These are packed in attractive cardboard boxes. During a week the store can sell a maximum of 400 shirts of type A and a maximum of 300 shirts of type B. The storage capacity, however, is limited to a maximum of 600 of both types combined. Type A shirt fetches a profit of SR 2/- per unit and type B a profit of SR. 5/- per unit. (a) Formulate a mathematical model of the problem.
Suppose that a package courier service promises to deliver to customers at 10:00 am on the morning after pickup. More than 1 hours from the promised delivery time is unacceptable to customers. Due to compensation that the company gives customers for not meeting the promised delivery target, the penalty is $19. How much variation should be allowed in the delivery service? Given : Op Cost = 19 -2.9D and Total Cost = 19 - 2.9D + 19D^2
Question: 100x^2-16y^6 Options: A. (10x+4y^3)(10x-4y^3) B. (100x+16^6)(100x-16y^6 C. (50x+8y^6)(50x-8y^6) D. 10x^2y^6(10x^2+y^6) PLEASE SHOW WORK
Suppose that a package courier service promises to deliver to customers at 10:00 am on the morning after pickup. More than 2 hours from the promised delivery time is unacceptable to customers. Due to compensation that the company gives customers for not meeting the promised delivery target, the penalty is $13. How much variation should be allowed in the delivery service? Given : Op Cost = 21 -1.7D and Total Cost = 21 - 1.7D + 3.25D^2 Solve in details
The maximum number of students to a group is 3. Only one project is to be submitted per group. This project must be uploaded to Canvas as a pdf no later than December 4th at 11:59 pm. Do not approximate any values unless you are asked to do so. This is very important! If you have a group of 2-3 people, please send me an email with the names in your group by the end of the day on Friday, November 4th and I will reply with your dimensions and unit costs for the project. If I don't hear from you by then, I will send out an email to random groups of three with your dimensions for the project. Please work together and check each other's work to minimize mistakes. You must get the dimensions and unit costs from me. Building the most economical shed (or minimizing the cost of building a shed). A shed is to be constructed based upon the figure below. The depth of the shed must be 1.6 times the length. Find the minimum cost to build the shed and the values of x and y that minimize the cost. 240…

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Maximize Z-150x1+125x2+95x3 Subject to Assembly Inspection 1.5x1 +1x2 +0.5x3 <=30 Packaging And x1, x2, x3 >=0 3 3.5x1 +2.75x2 +1.25x3 <= 150 1x1 +0.75x2 +0.25x3 <= 10