Maximize profit 4D + 3W With constraints Time 3D + 2W ≤ 150 Cost 2D + 4W ≤ 220 D, W ≥ 0 We saw the best point was (20, 45) with profit 215. Use this problem and the notes to answer the
Maximize profit 4D + 3W
With constraints
Time 3D + 2W ≤ 150
Cost 2D + 4W ≤ 220
D, W ≥ 0 We saw the best point was (20, 45) with profit 215. Use this problem and the notes to answer the
following (except part 4):
1 write true or false and then explain either response to this – the range of optimality on the D variable refers to how
much the value 20 in the best point can go down or go up and this point is still the best,
2 write true or false and the explain either response to this – the range of feasibility of the time constraint refers to
the value 150 and how much if can change and the best point is still (20, 45),
3 write true or false and explain either response to this – the shadow
the right hand side of the constraint (the 220) is anywhere between 100 and 300 then each 1 unit increase in this RHS
(say from 100 to 101) will increase profit by 12.5 cents and any 1 unit decrease in this RHS will decrease profit 12.5
cents,
4 write true or false and explain from information in section 8.6 of the text about the electronic communications
problem – On the model variable D the reduced cost of minus 45 means that if the company decided that instead of
making D = 0 as suggested in the solution but made D = 1 that profit would go up $45 from the original optimal value.
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