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Max Z=160x1 +200x2 %3D Subject to 2x1 +4x2 <40 (labor) 18x1 + 18x2 < 216 (wood) 24x1 +12x2 S 240 (storage space) x1, x2 20 Optimal tableau x1 x2 sl s2 s3 Basic 160 200 0. Var. x2 200 1/2 -1/18 0 8. x1 160 -1/2 1/9 0 4 s3 0. 6. -2 48 Z, 160 200 20 20/3 0. 2240 C; - Zj 0. -20 -20/3 0 1101 1410

Max Z=160x1 +200x2 %3D Subject to 2x1 +4x2 <40 (labor) 18x1 + 18x2 < 216 (wood) 24x1 +12x2 S 240 (storage space) x1, x2 20 Optimal tableau x1 x2 sl s2 s3 Basic 160 200 0. Var. x2 200 1/2 -1/18 0 8. x1 160 -1/2 1/9 0 4 s3 0. 6. -2 48 Z, 160 200 20 20/3 0. 2240 C; - Zj 0. -20 -20/3 0 1101 1410

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Exercise: Маx Z = 160x1 + 200x2 %3D Subject to 2x1 + 4x2 <40 (labor) 18x1 + 18x2 < 216 (wood) 24x1 + 12x2 S 240 (storage space) x1, x2 20 Optimal tableau xl x2 sl s2 s3 Basic 160 200 0. Var. x2 200 1 -1/18 0 8. -1/2 1/9 4. 160 0. x1 s3 0. -2 48 160 200 20 20/3 0. 2240 C - Z, 0 -20 -20/3 0 Determine the optimal ranges for q,
Transcribed Image Text:Exercise: Маx Z = 160x1 + 200x2 %3D Subject to 2x1 + 4x2 <40 (labor) 18x1 + 18x2 < 216 (wood) 24x1 + 12x2 S 240 (storage space) x1, x2 20 Optimal tableau xl x2 sl s2 s3 Basic 160 200 0. Var. x2 200 1 -1/18 0 8. -1/2 1/9 4. 160 0. x1 s3 0. -2 48 160 200 20 20/3 0. 2240 C - Z, 0 -20 -20/3 0 Determine the optimal ranges for q,
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