max Z = x1 + 3x2 + 5x3 4.x1 + 3x2 + 6x3 < 20 3x1 + 7x2 + 5x3 < 25 X1, X2, X3 > 0 Say we use x4, X5 as slack variables for the first and second constraint respectively. 8. If the objective changes to Z = 4x1 + 3x2 + 8x3. (a) Compute y" A - c". (b) why. Will the original optimal solution still be feasible and optimal? Explain What is the new optimal solution?

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Consider the following LP:
max Z = x1 + 3x2 + 5x3
4^1 + 322 + 6х3 < 20
3x1 + 7x2 + 5x3 < 25
X1, x2, x3 2 0
Say we use x4, x5 as slack variables for the first and second constraint respectively.
8. If the objective changes to Z = 4.x1 +3x2 + 8x3.
(a)
Compute y" A – c".
(b)
why.
Will the original optimal solution still be feasible and optimal? Explain
(c)
What is the new optimal solution?
Transcribed Image Text:Consider the following LP: max Z = x1 + 3x2 + 5x3 4^1 + 322 + 6х3 < 20 3x1 + 7x2 + 5x3 < 25 X1, x2, x3 2 0 Say we use x4, x5 as slack variables for the first and second constraint respectively. 8. If the objective changes to Z = 4.x1 +3x2 + 8x3. (a) Compute y" A – c". (b) why. Will the original optimal solution still be feasible and optimal? Explain (c) What is the new optimal solution?
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