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Engineering
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Max: 100 MW Cost: $20/MW Load: 50 MW G x1=0.2 p.u Cap: 50 MW. x2=0.2 Cap: 50 MW. x3=0.2 p.u. Cap: 50 MW. p.u. x4=0.2 p.u. Cap: 100 MW. 4 Max: 200 MW G Cost: $40/MW Load: 100 MW Load: 150 MW G Max: 250 MW Cost: $50/MW Example • Let's formulate the optimization problem for the following system. Max: 70 MW Cost: $30/MW Max: 80 MW Cost: $50/MW G x=0.1 p.u. Cap = 50 MW x=0.1 p.u. Cap = 50 MW x=0.1 p.u. Cap = 50 MW The VA base value is 100MVA 1 b = - = -10 p.u. x Objective: Subject to: Objective: Minimize (30P₁ +50P₂) Subject to: 0 ≤ P₁ ≤ 70 0 ≤ P₂ ≤ 80 −50 ≤ F₁3 ≤ 50 -50 ≤ F12 ≤ 50 -50 ≤ F23 ≤ 50 F1310 x 100(0₁ - 03) F12 10 x 100(0₁ - 0₂) F23 = 10 × 100(0₂ – 03) F12 = 0 P₁-F13 P₂ + F12 F23 = 0 F13 + F23 = 100 0₁ = 0 Load: 100 MW Minimize (30P₁ + 50P₂) 0 ≤ P₁ ≤ 70 0 ≤ P₂ ≤ 80 -50 ≤ F13 ≤ 50 -50 ≤ F12 ≤ 50 -50 ≤ F23 ≤ 50 F13 10 X 100 (0₁ - 03) F12 10 × 100(0₁ – 0₂) F23 = 10 x 100(02 - 03) F12 = 0 P₁ F13 P₂ + F12 Identify the variables and their ranges ● F23 = 0 F13 + F23 = 100 0₁ = 0 • Variables in this formulation: P1 P₂ F13 F12 • F23 0₁ (use a range of -1 to 1) 02 (use a range of -1 to 1) • 03 (use a range of -1 to 1)

Max: 100 MW Cost: $20/MW Load: 50 MW G x1=0.2 p.u Cap: 50 MW. x2=0.2 Cap: 50 MW. x3=0.2 p.u. Cap: 50 MW. p.u. x4=0.2 p.u. Cap: 100 MW. 4 Max: 200 MW G Cost: $40/MW Load: 100 MW Load: 150 MW G Max: 250 MW Cost: $50/MW Example • Let's formulate the optimization problem for the following system. Max: 70 MW Cost: $30/MW Max: 80 MW Cost: $50/MW G x=0.1 p.u. Cap = 50 MW x=0.1 p.u. Cap = 50 MW x=0.1 p.u. Cap = 50 MW The VA base value is 100MVA 1 b = - = -10 p.u. x Objective: Subject to: Objective: Minimize (30P₁ +50P₂) Subject to: 0 ≤ P₁ ≤ 70 0 ≤ P₂ ≤ 80 −50 ≤ F₁3 ≤ 50 -50 ≤ F12 ≤ 50 -50 ≤ F23 ≤ 50 F1310 x 100(0₁ - 03) F12 10 x 100(0₁ - 0₂) F23 = 10 × 100(0₂ – 03) F12 = 0 P₁-F13 P₂ + F12 F23 = 0 F13 + F23 = 100 0₁ = 0 Load: 100 MW Minimize (30P₁ + 50P₂) 0 ≤ P₁ ≤ 70 0 ≤ P₂ ≤ 80 -50 ≤ F13 ≤ 50 -50 ≤ F12 ≤ 50 -50 ≤ F23 ≤ 50 F13 10 X 100 (0₁ - 03) F12 10 × 100(0₁ – 0₂) F23 = 10 x 100(02 - 03) F12 = 0 P₁ F13 P₂ + F12 Identify the variables and their ranges ● F23 = 0 F13 + F23 = 100 0₁ = 0 • Variables in this formulation: P1 P₂ F13 F12 • F23 0₁ (use a range of -1 to 1) 02 (use a range of -1 to 1) • 03 (use a range of -1 to 1)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Please write down the formulation of the DCOPF problem for the 4-bus system provided in the first figure. I have provided an example of the formulation in Figure 2. Hope that helps

Max: 100 MW Cost: $20/MW Load: 50 MW G x1=0.2 p.u Cap: 50 MW. x2=0.2 Cap: 50 MW. x3=0.2 p.u. Cap: 50 MW. p.u. x4=0.2 p.u. Cap: 100 MW. 4 Max: 200 MW G Cost: $40/MW Load: 100 MW Load: 150 MW G Max: 250 MW Cost: $50/MW
Transcribed Image Text:Max: 100 MW Cost: $20/MW Load: 50 MW G x1=0.2 p.u Cap: 50 MW. x2=0.2 Cap: 50 MW. x3=0.2 p.u. Cap: 50 MW. p.u. x4=0.2 p.u. Cap: 100 MW. 4 Max: 200 MW G Cost: $40/MW Load: 100 MW Load: 150 MW G Max: 250 MW Cost: $50/MW
Example • Let's formulate the optimization problem for the following system. Max: 70 MW Cost: $30/MW Max: 80 MW Cost: $50/MW G x=0.1 p.u. Cap = 50 MW x=0.1 p.u. Cap = 50 MW x=0.1 p.u. Cap = 50 MW The VA base value is 100MVA 1 b = - = -10 p.u. x Objective: Subject to: Objective: Minimize (30P₁ +50P₂) Subject to: 0 ≤ P₁ ≤ 70 0 ≤ P₂ ≤ 80 −50 ≤ F₁3 ≤ 50 -50 ≤ F12 ≤ 50 -50 ≤ F23 ≤ 50 F1310 x 100(0₁ - 03) F12 10 x 100(0₁ - 0₂) F23 = 10 × 100(0₂ – 03) F12 = 0 P₁-F13 P₂ + F12 F23 = 0 F13 + F23 = 100 0₁ = 0 Load: 100 MW Minimize (30P₁ + 50P₂) 0 ≤ P₁ ≤ 70 0 ≤ P₂ ≤ 80 -50 ≤ F13 ≤ 50 -50 ≤ F12 ≤ 50 -50 ≤ F23 ≤ 50 F13 10 X 100 (0₁ - 03) F12 10 × 100(0₁ – 0₂) F23 = 10 x 100(02 - 03) F12 = 0 P₁ F13 P₂ + F12 Identify the variables and their ranges ● F23 = 0 F13 + F23 = 100 0₁ = 0 • Variables in this formulation: P1 P₂ F13 F12 • F23 0₁ (use a range of -1 to 1) 02 (use a range of -1 to 1) • 03 (use a range of -1 to 1)
Transcribed Image Text:Example • Let's formulate the optimization problem for the following system. Max: 70 MW Cost: $30/MW Max: 80 MW Cost: $50/MW G x=0.1 p.u. Cap = 50 MW x=0.1 p.u. Cap = 50 MW x=0.1 p.u. Cap = 50 MW The VA base value is 100MVA 1 b = - = -10 p.u. x Objective: Subject to: Objective: Minimize (30P₁ +50P₂) Subject to: 0 ≤ P₁ ≤ 70 0 ≤ P₂ ≤ 80 −50 ≤ F₁3 ≤ 50 -50 ≤ F12 ≤ 50 -50 ≤ F23 ≤ 50 F1310 x 100(0₁ - 03) F12 10 x 100(0₁ - 0₂) F23 = 10 × 100(0₂ – 03) F12 = 0 P₁-F13 P₂ + F12 F23 = 0 F13 + F23 = 100 0₁ = 0 Load: 100 MW Minimize (30P₁ + 50P₂) 0 ≤ P₁ ≤ 70 0 ≤ P₂ ≤ 80 -50 ≤ F13 ≤ 50 -50 ≤ F12 ≤ 50 -50 ≤ F23 ≤ 50 F13 10 X 100 (0₁ - 03) F12 10 × 100(0₁ – 0₂) F23 = 10 x 100(02 - 03) F12 = 0 P₁ F13 P₂ + F12 Identify the variables and their ranges ● F23 = 0 F13 + F23 = 100 0₁ = 0 • Variables in this formulation: P1 P₂ F13 F12 • F23 0₁ (use a range of -1 to 1) 02 (use a range of -1 to 1) • 03 (use a range of -1 to 1)
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