0.7000 7.Matrix AddressingTo refer to the element in row and column of matrix x, y(row,coumn)>> x=[16 13 19 19, 182 19/10; 3 6 3 16; 18 11 19 3]>> x(3,3) ans €3>> x(3,:) ans =36316To create a submatrix using the colon operator:>> y=x(2:end, Dend-1)y= 18 2 1936318 11 19>> z= y(1:22:3)Z-2 1963رو میاد که یه وه(13)

Answered: Matrix Ad To refer to the element in…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Similar questions

1. Write two ways to display the following matrix 3 4 5 6 ( 13 14 15 16 17 2. 4 3 3 4 Let A 9 6 a) using the columns operator (:) , creat a column vector that contains all the columns of A. b) using the columns operator (:) , creat a column vector that contains all the Rows of A. c) using the columns operator (:),creat a Row vector that contains the 1*t row and 3rd columns of A. d) using the columns operator (:) , creat a column vector that contains all the columns of A. e) using the columns operator (:) , creat a column vector that contains all the columns of A.
plz solve the b and c part here is the a part #include<iostream> using namespace std; //main functionint main(){ //declare d1 for degree int d1; //asking user to enter degree cout<<"Degree of the polynomial : "; cin>>d1; //declare array int A1[d1 + 1]; //asking user to enter coefficient cout<<"Enter coefficient for each term from highest degree to the lowest degree : "; for(int i = 0; i <= d1; i++) cin>>A1[i]; //declare variables int k = d1; //for loop to print polynomial for( int i = 0; i <= d1; i++,k--){ //when coefficient value is not 0 nor 1 if(A1[i] !=0 && A1[i] != 1 ){ //print polynomial with variable if(i != d1 && i != d1-1){ cout<<A1[i]; cout<<"x^"<<k; } //when it is 2nd last coefficient if(i == d1-1)…
Game of Hunt in C++ language Create the 'Game of Hunt'. The computer ‘hides’ the treasure at a random location in a 10x10 matrix. The user guesses the location by entering a row and column values. The game ends when the user locates the treasure or the treasure value is less than or equal to zero. Guesses in the wrong location will provide clues such as a compass direction or number of squares horizontally or vertically to the treasure. Using the random number generator, display one of the following in the board where the player made their guess: U# Treasure is up ‘#’ on the vertical axis (where # represents an integer number). D# Treasure is down ‘#’ on the vertical axis (where # represents an integer number) || Treasure is in this row, not up or down from the guess location. -> Treasure is to the right. <- Treasure is to the left. -- Treasure is in the same column, not left or right. +$ Adds $50 to treasure and no $50 turn loss. -$ Subtracts…

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