Answered: material at T = 300 K is 5.50 eV. The…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Question 2: The Fermi energy level for a particular material at T = 300 K is 5.50 eV. The electrons in this material follow the Fermi-Dirac distribution function. a) Find the probability of an energy level at 5.50 eV being occupied by an electron. b) Repeat part (a) if the temperature is increased to T = 600 K. (Assume that EF is a constant.). c) Calculate the energy level where probability of finding an electron at room temperature is 70%. d) Calculate the temperature at which there is a 7 percent probability that a state 0.4 eV below the Fermi level will be empty of an electron. Please use formula below

Physical Constants
h = 1.055 x 10-34 J.s
mo = 9.109 x 10-³1 Kg
K = 1.388 x 10-23 J/K
q = 1.602 x 10-1⁹ C
Density of States
9c(E)=
Fermi Function
Formula Sheet
mn√2m (EEc)
π² x ħ³
mn
mp
Ks
f(E)=
Semiconductor Parameters
Ge
0.56mo
0.4mo
16
&o=8.854 x 10-1² F/m
KT|T=300K = 0.026 eV
Es = Ks X Eo
1
9v (E)=
E-EE
1+eKT
GaAs
0.067mo
0.5mo
12.9
mp√ √2mp(Ev - E)
π² x ħ³
Si
1.18mo
0.8mo
11.9

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