matching the steps

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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matching the steps

اختیار [
It follows that -a = (-q)d-r =
(-q-1)d+(d-r).
%3D
If d I a, then a = md for some
integer m, and it follows that -a =
(-m)d as well.
Note that 0 < d-r < d, so by definition
(-a) div d = -q-1. But -(a div d) =
-q,
Conversely, if d does not divide a,
O then a = qd + r for some r with 0 <r <
d. Here q = a div d.
%3D
Therefore, -(a div d) = -m and (-a)
div d = -m, as desired.
%3D
so (-a) div d = -(a div d).
Transcribed Image Text:اختیار [ It follows that -a = (-q)d-r = (-q-1)d+(d-r). %3D If d I a, then a = md for some integer m, and it follows that -a = (-m)d as well. Note that 0 < d-r < d, so by definition (-a) div d = -q-1. But -(a div d) = -q, Conversely, if d does not divide a, O then a = qd + r for some r with 0 <r < d. Here q = a div d. %3D Therefore, -(a div d) = -m and (-a) div d = -m, as desired. %3D so (-a) div d = -(a div d).
Show that if a and d are positive
integers, then (-a) div d = -a div d if
.and only if d divides a
Reorder the following steps (From
Step 01 to step 06) to proof the
? above statement
اختیار
Step 01
اختیار[
Step 02
اختیار [
Step 03
اختیار
Step 04
اختیار
Step 05
Step 06
اختیار [
Transcribed Image Text:Show that if a and d are positive integers, then (-a) div d = -a div d if .and only if d divides a Reorder the following steps (From Step 01 to step 06) to proof the ? above statement اختیار Step 01 اختیار[ Step 02 اختیار [ Step 03 اختیار Step 04 اختیار Step 05 Step 06 اختیار [
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