ABFA(x) = 10 (a+(k– 1)Ax)Ax +r(x}(x- left(x) if x 2ak-1CD E Match what the circled expression mean in terms of the quantities they evaluate. Click here to get a page to print, if desired.Choose a letter from the list given below so the statements are labeled appropriately.)the accumulation due to one completed intervalthe variation in z in the current interval|the accumulation due to all completed intervalsthe number of completed intervalsthe rate of change of the current interval) the accumulation due to the current intervalSubmit

Name: ABFA(x) = 10 (a+(k– 1)Ax)Ax +r(x}(x- left(x) if x 2ak-1CD E Match wha
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Description: ABFA(x) = 10 (a+(k– 1)Ax)Ax +r(x}(x- left(x) if x 2ak-1CD E Match what the circled expression mean in terms of the quantities they evaluate. Click here to get a page to print, if desired.Choose a letter from the list given below so the statements ar

The given equation Ax=10∑k=1x-a∆xra+k-1∆x∆x+rxx-leftx if x≥a The alphabet can be matched as…

Answered: Match what the circled expression mean…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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A
B
F
A(x) = 10 (a+(k– 1)Ax)Ax +r(x}(x- left(x) if x 2a
k-1
C
D E

Match what the circled expression mean in terms of the quantities they evaluate. Click here to get a page to print, if desired.
Choose a letter from the list given below so the statements are labeled appropriately.
)the accumulation due to one completed interval
the variation in z in the current interval
|the accumulation due to all completed intervals
the number of completed intervals
the rate of change of the current interval
) the accumulation due to the current interval
Submit

Expert Solution

Step 1

The given equation

$A (x) = 10 ((\sum_{k = 1}^{|\frac{x - a}{∆ x}|} r (a + (k - 1) ∆ x) ∆ x) + r (x) (x - l e f t (x))) i f x \geq a$

The alphabet can be matched as

$A = (\sum_{k = 1}^{|\frac{x - a}{∆ x}|} r (a + (k - 1) ∆ x) ∆ x) -$ The accumulation due to all completed intervals.

$B = |\frac{x - a}{∆ x}| -$ The number of completed intervals

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