Match the trigonometric expression with its simplified form. sec²(x) - 1 sin²(x) 01 O sec²(x) 0-1 O sin(x) tan(x) O sec(x) csc(x)

Q: 1 + tan² dx

A:

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A: The integration can be written as;

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A: We have to evaluate  ∫cos4(2x) sin(2x) dx.

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A:

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A:

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A: We know, Sin(x) = Cos(90°-x)

Q: (csc²(x)-csc(x)) cot(x) dx CsS

A: The given integral is: ∫csc2x-cscxcotx dx So, we have: I=∫csc2x-cscxcotx dx

Q: cos x csc3 x + C sin4 x 1.

A: To evaluate the given integral.

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A: Given

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A:

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A: Given integral is, ∫xsin(3x2)cos(6x2)dx

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A: To find the value of

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A:

Q: Let f(æ) = 9 sin(cos(x²)) || f' (x) =

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Q: d30 Find dr30 (-15 sin (x)).

A: