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Match the steps (in the right column) to their corresponding step numbers (in the left column) to solve the recurrence relation an=-6an-1-9an - 2 for nz 2 together with the initial conditions ao = 3 and a₁ = -3. 1 Step 1 2 Step 2 Match each of the options above to the items below. The general solution is an = a₁(-3) + a2n(-3)^. 3 The characteristic equation and its roots are 2 +6r+ 9 = 0 and r= -3, -3, respectively. Using initial conditions, 3 = a₁ and -3 = -3a₁-3a2 Step 4 After solving, a₁ = 3 and a2 = -2. Therefore, an=3(-3) -2n(-3) = (3-2n)(-3)". 4 Step 3 ▶

Match the steps (in the right column) to their corresponding step numbers (in the left column) to solve the recurrence relation an=-6an-1-9an - 2 for nz 2 together with the initial conditions ao = 3 and a₁ = -3. 1 Step 1 2 Step 2 Match each of the options above to the items below. The general solution is an = a₁(-3) + a2n(-3)^. 3 The characteristic equation and its roots are 2 +6r+ 9 = 0 and r= -3, -3, respectively. Using initial conditions, 3 = a₁ and -3 = -3a₁-3a2 Step 4 After solving, a₁ = 3 and a2 = -2. Therefore, an=3(-3) -2n(-3) = (3-2n)(-3)". 4 Step 3 ▶

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Match the steps (in the right column) to their corresponding step numbers (in the left column) to solve the recurrence relation an=-6an-1-9an - 2 for n≥ 2 together with the initial conditions ao = 3 and a₁ = -3. Step 1 2 Step 2 Match each of the options above to the items below. The general solution is an = a₁(−3)” + a2n(−3)”. 3 The characteristic equation and its roots are 2 + 6r+ 9 = 0 and r= -3, -3, respectively. Using initial conditions, 3 = a₁ and -3 = -3a₁-3a2 Step 4 After solving, a₁ = 3 and a2 = -2. Therefore, an = 3 · (–3)″ −2n(−3)″ = (3 – 2n)(–3)″. Step 3 ← ◄►
Transcribed Image Text:Match the steps (in the right column) to their corresponding step numbers (in the left column) to solve the recurrence relation an=-6an-1-9an - 2 for n≥ 2 together with the initial conditions ao = 3 and a₁ = -3. Step 1 2 Step 2 Match each of the options above to the items below. The general solution is an = a₁(−3)” + a2n(−3)”. 3 The characteristic equation and its roots are 2 + 6r+ 9 = 0 and r= -3, -3, respectively. Using initial conditions, 3 = a₁ and -3 = -3a₁-3a2 Step 4 After solving, a₁ = 3 and a2 = -2. Therefore, an = 3 · (–3)″ −2n(−3)″ = (3 – 2n)(–3)″. Step 3 ← ◄►
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